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3 years ago

A 1.6 Kg bird that is flying through the air has 220 J of kinetic energy. How fast is the bird flying?

Physics

1 answer:

xxTIMURxx [149]3 years ago

3 0

Answer:

v = 16.58 m/s

Explanation:

Given that,

Mass of a bird, m = 1.6 kg

Kinetic energy of the bird, K = 220 J

We need to find the speed of the bird. The formula for the kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Where

v is the speed of the bird

So,

$v=\sqrt{\dfrac{2E}{m}}$

Put all the values,

$v=\sqrt{\dfrac{2\times 220}{1.6}}\\\\v=16.58\ m/s$

So, the speed of the bird is equal to 16.58 m/s.

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What are the SI units of thermal conductivity?

kotykmax [81]

Answer:

The SI unit of thermal conductivity is watts per meter-kelvin (W/(m⋅K)).

Explanation:

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2 years ago

Four complete waves pass the duck in one second the frequency of this wave is

galben [10]

The frequency of a wave is the number of complete oscillations passing a given point per second.

In this case, assuming the duck is stationary, we have 4 complete waves passing the duck in one second: therefore, the frequency of the wave is
$f= \frac{4}{1 s}=4 Hz$

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3 years ago

A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to

Svetach [21]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

F = $5.20 \times 10^{5}$ N

g = 9.8 m/s

radius = $\frac{diameter}{2}$

= $\frac{30 cm}{2}$ = 15 cm = 0.15 m (as 1 m = 100 cm)

Formula to calculate depth is as follows.

F = $\rho \times g \times h \times A$

or, h = $\frac{F}{\rho \times g \times A}$

h = $\frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}$

= 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

3 0

3 years ago

An ideal battery would produce an extraordinarily large current if "shorted" by connecting the positive and negative terminals w

liubo4ka [24]

Answer:

Resistance, $R=0.529\ \Omega$

Explanation:

Given that,

Voltage of the battery, V = 9 volts

Current produced in the circuit, I = 17 A

We need to find the resistance when shorted by a wire of negligible resistance. It is a case of Ohm's law. The voltage is given by :

$V=IR$

$R=\dfrac{V}{I}$

$R=\dfrac{9\ V}{17\ A}$

$R=0.529\ \Omega$

So, the resistance in the circuit is 0.529 ohms. Hence, this is the required solution.

6 0

3 years ago

1 point

WINSTONCH [101]

Answer:

Mg- 27 means isotope with 12 protons and 15 neutrons.

Also 27 is mass number which express sum of protons and neutrons.

In nucleus one neutrn decays to electron and proton. Mass number remain same but Al-27 nucleus contain 13 protons and 14 neutrons. Electron is ejected out from nucleus.

7 0

3 years ago