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2 years ago

A 1.6 Kg bird that is flying through the air has 220 J of kinetic energy. How fast is the bird flying?

Physics

1 answer:

xxTIMURxx [149]2 years ago

3 0

Answer:

v = 16.58 m/s

Explanation:

Given that,

Mass of a bird, m = 1.6 kg

Kinetic energy of the bird, K = 220 J

We need to find the speed of the bird. The formula for the kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Where

v is the speed of the bird

So,

$v=\sqrt{\dfrac{2E}{m}}$

Put all the values,

$v=\sqrt{\dfrac{2\times 220}{1.6}}\\\\v=16.58\ m/s$

So, the speed of the bird is equal to 16.58 m/s.

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In the diagram, q1= -2.60*10^-9 C and

Alekssandra [29.7K]

Answer:

The magnitude of the net electric field is:

$E_{net}=90.37\: N/c$

Explanation:

The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).

On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).

Knowing this, the <u>magnitude of the net electric</u> field will be the<u> E1 + E2. </u>

Let's find first E1 and E2.

The electric field equation is given by:

$|E_{1}|=k\frac{|q_{1}|}{d_{1}^{2}}$

Where:

k is the Coulomb constant (k = 9*10^{9} Nm²/C²)
q1 is the first charge
d1 is the distance from q1 to P

$|E_{1}|=(9*10^{9})\frac{|-2.60*10^{-9}|}{0.538^{2}}$

$|E_{1}|=80.84\: N/C$

And E2 will be:

$|E_{2}|=k\frac{|q_{2}|}{d_{2}{2}}$

$|E_{2}|=(9*10^{9})\frac{|-8.30*10^{-9}|}{1.36^{2}}$

$|E_{2}|=40.39\: N/C$

Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.

$E_{net}=\sqrt{E_{1}^{2}+E_{2}^{2}}$

$E_{net}=\sqrt{80.84^{2}+40.39^{2}}$

$E_{net}=90.37\: N/c$

I hope it helps you!

7 0

2 years ago

What are the characteristics and ph level of acids?

12345 [234]

General Characteristics of Acids & Bases. Chemists measure the strength of an acid or base by its pH, which is a term that refers to the "power of hydrogen.". The midpoint of the pH scale is neutral. Compounds with a pH lower than the midpoint value are acidic while those with a higher value are basic or alkaline.

7 0

3 years ago

Suppose you could fit 100 dimes, end to end, between your card with the pinhole and your dime-sized sunball. how many suns could

Naddika [18.5K]

Answer: 100 suns

Explanation:

We can solve this with the following relation:

$\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}$