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3 years ago

Which of the following is required for work to be done on an object?

Physics

1 answer:

ad-work [718]3 years ago

7 0

I think that in order for work to be done, the object must move in the direction of the force and move over a distance.

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What is the main function of a protein within the body?

aksik [14]

The answer looks to be "A" because Protein is used to regulate organs.

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3 years ago

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Is the arctic ocean larger than the indian ocean?

Alik [6]

The Arctic Ocean is the smallest ocean. It is more than five times smaller than Indian and Atlantic Oceans.

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3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

A child bounces a 48 g superball on the sidewalk. the velocity change of the superball is from 26 m/s downward to 17 m/s upward.

Nataly_w [17]

By definition we have the momentum is:
P = m * v
Where,
m = mass
v = speed
Before the impact:
P1 = (0.048) * (26) = 1.248 kg * m / s
After the impact:
P2 = (0.048) * (- 17) = -0.816 Kg * m / s.
Then we have that deltaP is:
deltaP = P2-P1
deltaP = (- 0.816) - (1,248)
deltaP = -2,064 kg * m / s.
Then, by definition:
deltaP = F * delta t
Clearing F:
F = (deltaP) / (delta t)
Substituting the values
F = (- 2.064) / (1/800) = - 1651.2N
answer:
the magnitude of the average force exerted on the superball by the sidewalk is 1651.2N

3 0

4 years ago

G=(6.67x10^-11 Nm^2/Kg^2)(6.4x10^23 Kg)<br> /3396km^2

QveST [7]

Answer:

search it up baby girl

Explanation:

7 0

3 years ago