Answer:
X = 15.88 m
Explanation:
Given:
Initial Velocity V₀ = 13.4 m/s
θ = 30.1 °
g = 9.8 m/s²
To Find horizontal distance let "X" we have to time t first.
so from motion 2nd equation at Height h = 0
h = V₀y t + 1/2 (-g) t ² (ay = -g)
0 = 13.4 sin 30.1° t - 0.5 x 9.81 x t² (V₀y = V₀ Sin θ)
⇒ t = 1.37 s
Now For Horizontal distance X, ax =0m/s²
X = V₀x t + 1/2 (ax) t ²
X = 13.4 m × cos 30.1° x 1.37 s + 0
X = 15.88 m
(a) James has the most momentum which is 294 kgm/s.
(b) The resultant force acting on Basma is 90.78 N.
(c) The time taken for James to stop is 3.2 seconds.
<h3>
Momentum of each person</h3>
Momentum of James: P = mv = 98 x 3 = 294 kgm/s
Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s
<h3>Resultant force of Basma</h3>
F = ma = mv/t = P/t = 236/2.6 = 90.78 N
<h3>Time for James to stop</h3>
F = P/t
t = P/F
t = 294/90.78
t = 3.2 s
Learn more about momentum here: brainly.com/question/7538238
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I think its 1x^103 (kg/m.3) I hope this help
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