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Alex73 [517]
3 years ago
11

The acceleration due to gravity is lower on the Moon than on Earth. Which one of the following statements is true about the mass

and weight of an astronaut on the Moon's surface, compared to Earth?
a) Mass is the same, weight is less.
b) Both mass and weight are the same.
c) Mass is less, weight is the same.
d) Both mass and weight are less.
Physics
2 answers:
Strike441 [17]3 years ago
8 0

Answer:

a) Mass is the same, weight is less.

Explanation:

As we know that the mass of the object is the measurement of the quantity of the matter that is present in it

So here we can say that if the mass of the object is m then its total quantity of the matter that is present in it is given as

mass = (density)\times (volume)

Now for the weight of the object is defined as the force of gravity due to planet

F_g = mg

so the weight of the object is depending on the acceleration due to gravity of the planet

As we know that the gravity of moon is smaller than the gravity of the earth so here weight on the moon will be smaller than the weight on the Earth

so correct answer will be

a) Mass is the same, weight is less.

Helga [31]3 years ago
4 0
mass is the same, weight is less because weight =mass ×gravity
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Answer:

However, the disadvantages are:

1. Many atimes for some motion prolems, free-body diagrams has to be drawn many times so to have enough equations to solve for the unknowns. This is not the same with energy conservation principles.

2. In situations where we need to find the internal forces acting on an object, we can't truly solve such problems using free-body diagram as it captures external forces. This is not the same with energy conservation principles.

Explanation:

Often times the ideal method to use in solving motion problem related questions are mostly debated.

Energy conservation principles applies to isolated systems are useful when object changes their positions in moving upward or downward converts its potential energy due to gravity for kinetic energy, or the other way round. When energy in a system or motion remains constant that is energy is neither created nor destroyed, it can therefore be easier to calculate other unknown paramters like in the motion problem velocity, distance bearing it in mind that energy can only change from one type to another.

On the other hand, free body diagram which is a visual representation of all the forces acting on an object including their directions has so many advantages in solving motion related problems which include finding relationship between force and motion in identifying the force acting on a body.

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2 years ago
Please, I need help with this.
solmaris [256]

this is the answer :)

6 0
3 years ago
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3 years ago
Freezing involves the ______________ of latent heat and a change is state from the ______________ phase to the solid phase.
DaniilM [7]
<span>Freezing involves the decrease in value of latent heat by 80 Cal/gm and a change of state from the Liquid phase to the solid phase.

So, in short, Fill in the blank as follows:
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7 0
3 years ago
An 80-kg man is skating northward and happens to suddenly collide with a 20-kg boy who is ice skating toward the east. Immediate
Fantom [35]

Answer:

6.25 m/s

Explanation:

mass of man (m1) = 80 kg

mass of boy (m2) = 20 kg

mass of man and boy after collision (m12)= 20 + 80 = 100 kg

velocity of man and boy after collision (v) = 2.5 m/s

angle θ = 60 °

How fast was the boy moving just before the collision ?

  • From the diagram attached, the first image shows the man and the boys motion while the second diagram shows their motion rearranged to form a triangle. With the momentum of the man and the boy forming the sides of the triangle.
  • M₁₂ =  total momentum after collision = m12 x v = 100 x 2.5 = 250
  • Mboy = momentum of the boy before collision = m2 x Velocity of boy
  • Mman = momentum of the man before collision = m1 x velocity of man  
  • from the triangle, cos θ = \frac{Mboy}{M₁₂}

        cos 60 = \frac{Mboy}{250}

        Mboy = 250 x cos 60 = 125

  • recall that momentum of the boy (Mboy) also = m2 x Velocity of boy

        therefore

        125 = 20 x velocity of boy

         velocity of boy = 125 / 20 = 6.25 m/s

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3 years ago
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