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Anarel [89]
2 years ago
15

Which is the answer for this question

Physics
2 answers:
Mariulka [41]2 years ago
5 0
The both carry energy
Brut [27]2 years ago
3 0

Explanation:

Light is not invisible

sound cant travel in a vacuum

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Can anyone ask me how many protons, neutrons, and electrons I need and just explain where to put them.​
Aliun [14]

Answer:

on the first shell (ring) there will be 2 electrons

and on the 2nd shell there will be only one electron

while in the nucleus (the middle of the diagram) there will be 4 neutrons and 3 protons

Explanation:

 you can see the picture attached

8 0
3 years ago
A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 8
alexgriva [62]

Answer:

the final pressure of the gas is 60 kPa.

Explanation:

Given;

initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa

initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k

final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K

Let the final pressure of the gas = P₂

Apply pressure law;

\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300}  = 60,000 \ Pa = 60 \ kPa

Therefore, the final pressure of the gas is 60 kPa.

4 0
3 years ago
The older, geocentric model of the solar system placed the__________ at the center. Today's heliocentric model places the_______
DedPeter [7]

the answer is earth for the first one and sun for the second one

3 0
3 years ago
Read 2 more answers
The gravitational attraction between two masses of 3kg that are separated by a distance of 1cm is
Luba_88 [7]

Answer:

6.003×10¯⁶ N

Explanation:

We'll begin by converting 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Finally, we shall determine the gravitational attraction. This can be obtained as follow:

Mass 1 (M₁) = 3 Kg

Mass 2 (M₂) = 3 Kg

Distance apart (r) = 0.01 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 3 × / 0.01²

F = 6.003×10¯¹⁰ / 1×10¯⁴

F = 6.003×10¯⁶ N

Thus the gravitational attraction is 6.003×10¯⁶ N

6 0
3 years ago
20 POINTS PLUS BRAINLIEST What work is done by a system on its environment when an ideal gas is maintained at a constant pressur
Oliga [24]

Say you have 60 cubic meters of an ideal gas at a pressure of 200 pascals. You heat the gas until it expands to a volume of 120 cubic meters. How much work does the gas do? All you have to do is plug in the numbers:

The gas does 12,000 joules of work as it expands under constant pressure.


4 0
3 years ago
Read 2 more answers
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