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Phoenix [80]
3 years ago
12

A vehicle with a manual transaxle can be cranked and started without depressing the clutch pedal. Technician A says the clutch i

s not releasing when the pedal is depressed. Technician B says the most likely cause is a defective clutch safety switch. Who is correct?
Physics
1 answer:
SashulF [63]3 years ago
6 0

Answer: Technician B

Explanation: In manual cars,the clutch safety is designed to stop the vehicle from moving when you start the gnition. It prevents power from flowing into the circuit . This is found in the pedal mechanism of cars so depressing the clutch pedal will likely cause a defective in the clutch safety. You will begin to perceive the clutch burning and white fumes coming out from the pedal.

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Two charges, Q1 and Q2, are separated by 6·cm. The repulsive force between them is 25·N. In each case below, find the force betw
Misha Larkins [42]

Answer:

a) 5 N b) 225 N c) 5 N

Explanation:

a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of  the distance between them, acting along  the  line that joins the charges, as follows:

F₁₂ = K Q₁ Q₂ / r₁₂²

So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N

b) If we reduce the distance, from r, to r/3, as the  factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.

So, we will have F₁₂ = 9. 25 N = 225 N

c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:

F₁₂ = 25 N .1/5 = 5 N

3 0
3 years ago
Given that an electric field of 3×106V/m3×106V/m is required to produce an electrical spark within a volume of air, estimate the
Andre45 [30]

Answer:

Length, l = 33.4 m

Explanation:

Given that,

Electrical field, E=3\times 10^6\ V/m

Let the electrical potential is, V=10^8\ V

We need to find the length of a thundercloud lightning bolt. The relation between electric field and the electric potential is given by :

V=E\times d\\\\d=\dfrac{V}{E}\\\\d=\dfrac{10^8}{3\times 10^6}\\\\d=33.4\ m

So, the length of a thundercloud lightning bolt is 33.4 meters. Hence, this is the required solution.

5 0
3 years ago
Which of the following best describes gravitational force?
miss Akunina [59]

Answer:

An attraction between two objects that have mass :)

7 0
2 years ago
While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizo
Viefleur [7K]

Answer:

The horizontal force is 106.89 N.

Explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

W= Fd\cos\theta

Where, \theta=0^{\circ}

W=F\cdot d

Put the value into the formula

310=F\cdot 2.9

F=\dfrac{310}{2.9}

F=106.89\ N

Hence, The horizontal force is 106.89 N.

3 0
3 years ago
If the spring constant k of a pogo stick is 3500 N m and the weight of the person on the pogo stick is 700 N, how much is the sp
algol [13]

As we know that spring force is given by

F = kx

here we know that

F = 700 N

also we know that

k = 3500 N/m

now from above equation we will have

700 = 3500 (x)

now we will have

x = \frac{700}{3500}

x = \frac{1}{5} m = 20 cm

so here we can say that end of the spring will be compressed by 20 cm

6 0
3 years ago
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