Louisa found that she could melt 150g of lead at 3275 C. At what temperature could she melt 75g of lead?

Help please ill give brainly and heart !!!!

Nikitich [7]

Answer:

The answer is A ) High pressure

I hope this helps you :)

please let me know if I am wrong

3 0

3 years ago

Read 2 more answers

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t

diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

-30 = 5V0 - 122.5

-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

this is the initial speed of the egg

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

342.25-19.6y = 0

342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

this value is how high it rises above starting point

3.

The magnitude of velocity is = 0 at its highest point

4.

This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.

5. Please check attachment for graph

6 0

3 years ago

Calculate the ionization potential for C+5 ( 5 electrons removed for the C atom) and in addition compute the wavelength of the t

sveta [45]

Answer:

Ionization potential of C⁺⁵ is 489.6 eV.

Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.

Explanation:

The ionization potential of hydrogen like atoms is given by the relation :

$E = \frac{13.6Z^{2} }{n^{2} } eV$ .....(1)

Here E is ionization potential, Z is atomic number and n is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for Z and 1 for n in the equation (1).

$E = \frac{13.6\times(6)^{2} }{1^{2} }$

 E = 489.6 eV

The wavelength (λ) of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

$\frac{1}{\lambda} =RZ^{2}[\frac{1}{n_{1} ^{2}}-\frac{1}{n_{2} ^{2} }]$ ......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

$\frac{1}{\lambda} =1.09\times10^{7} \times6^{2}[\frac{1}{2 ^{2}}-\frac{1}{3 ^{2} }]$

$\frac{1}{\lambda}$ = 5.45 x 10⁷

λ = 1.83 x 10⁻⁸ m

7 0

3 years ago

A Newton is 1 kgm/s2 . Is this a fundamental unit or a derived unit?

wolverine [178]

This is a derived unit. It's a combination of the units for mass, length, and time.

3 0

3 years ago

If a beam of electromagnetic radiation has an intensity of 120 W/m2, what is the maximum value of the electric field?

Ivan

Answer:

Electric field, E = 300.65 N/C

Explanation:

Given that,

Intensity of a beam of electromagnetic radiation, $I=120\ W/m^2$

We need to find the maximum value of the electric field. The intensity of electromagnetic wave in terms of electric field is given by :

$I=\dfrac{1}{2}\epsilon_oE^2c$

c is the speed of light

$E=\sqrt{\dfrac{2I}{\epsilon_o c}}$

$E=\sqrt{\dfrac{2\times 120}{8.85\times 10^{-12}\times 3\times 10^8}}$

E = 300.65 N/C

So, the maximum value of the electric field is 300.65 N/C. Hence, this is the required solution.

6 0

3 years ago