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2 years ago

Louisa found that she could melt 150g of lead at 3275 C. At what temperature could she melt 75g of lead?

Physics

1 answer:

Oksana_A [137]2 years ago

4 0

She could melt 75g of lead at 1637.5 C

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A small car of mass m and a large car of mass 4m drive along a highway at constant speeds VS and VL. They approach a curve of ra

Arte-miy333 [17]

Answer:

$v_S=\sqrt{2}v_L$

Explanation:

The acceleration experimented while taking a curve is the centripetal acceleration $a=\frac{v^2}{r}$ . Since $a_S=2a_L$ , we have that: $\frac{v_S^2}{r_S}=\frac{2v_L^2}{r_L}$

They take the same curve, so we have: $r_S=r_L=R$

Which means: $v_S^2=2v_L^2$

And finally we obtain: $v_S=\sqrt{2}v_L$

4 0

3 years ago

Excellent human jumpers can leap straight up to a height of

Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.

We can calculate the initial speed to reach 110 cm of height with the following equation:

$v_{f}^{2} = v_{i}^{2} - 2gh$

Where:

$v_{f}$ : is the final speed = 0 (at the maximum height of 110 cm)

$v_{i}$ : is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the initial velocity is:

$v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s$

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0

2 years ago

A published hypothesis:

kow [346]

Answer:

should be tested by the scientific community

4 0

2 years ago

Which objects are opaque? Check all that apply.

Vinvika [58]

textbook
track shoes
basketball

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2 years ago

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Svet_ta [14]

Oki said he would not hood him to go on a bike but i said he would be ok if you don’t have a ride home with you and green one for a

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2 years ago