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Korvikt [17]
3 years ago
11

An undamped 1.48 kg horizontal spring oscillator has a spring constant of 35.4 N/m. While oscillating, it is found to have a spe

ed of 3.90 m/s as it passes through its equilibrium position. What is its amplitude A of oscillation
Physics
1 answer:
givi [52]3 years ago
5 0

Answer: 0.798 m

Explanation:

Given

Mass of the spring oscillator, m = 1.48 kg

Force constant of the spring, k = 35.4 N/m

Speed of oscillation, v = 3.9 m/s

Kinetic Energy = 1/2 mv²

Kinetic Energy = 1/2 * 1.48 * 3.9²

KE = 0.5 * 22.5108

KE = 11.26 J

Using the law of conservation of Energy. The Potential Energy of the system is equal to Kinetic Energy of the system

KE = PE

PE = 1/2kx²

11.26 = 1/2 * 35.4 * x²

11.26 = 17.7x²

x² = 11.26 / 17.7

x² = 0.6362

x = √0.6362

x = 0.798 m

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A bag of cement has a mass of 62 g. What is the mass of the bag of cement in S.I. units (kg)?
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The mass of this bag of cement in S.I. units (kg) is equal to 0.062 kilograms.

<u>Given the following data:</u>

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To calculate the mass of this bag of cement in S.I. units (kg):

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In Science, kilograms (kg) is the standard unit of measurement or S.I. units of the mass of a physical object. Thus, we would convert the value of the mass of this bag of cement in grams to kilograms (kg) as follows:

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