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masha68 [24]
3 years ago
9

A rabbit is hopping towards a clover patch. It has energy. The rabbit weighs 1kg and hops with a velocity of 20 m/s, calculate t

he rabbit's kinetic energy.
Physics
1 answer:
laila [671]3 years ago
6 0

Answer:200j

Explanation:

mass(m)=1kg

Velocity(v)=20m/s

Kinetic energy=(m x v^2) ➗ 2

Kinetic energy =(1 x 20^2) ➗ 2

Kinetic energy=(1 x 20 x 20) ➗ 2

Kinetic energy=400 ➗ 2

Kinetic energy =200j

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Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

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W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

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