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4 years ago

Help can anyone answer this please

Chemistry

1 answer:

attashe74 [19]4 years ago

5 0

Answer:

Ionic compounds

Explanation:

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The most important ore of aluminum is _____ show the chemical formula .

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Answer:

The most important ore of aluminum is Bauxite.

And its chemical formula is $Al_2O_3.2H_2O$ .

Explanation:

Bauxite is the most important ore of Aluminium from which Aluminium is extracted. Bauxite is a rock and composed of Aluminium bearing mineral.

And its chemical formula is $Al_2O_3.2H_2O$ .

It contains Gibbsite, Bohmite and Diaspore along with iron.

It is a soft material with somewhat white to grey to reddish brown in colour.

It has an earthy lustre and low specific gravity.

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4 years ago

Match the following metric terms. 1. the basic measure of mass in the metric system meter 2. prefix meaning one-hundredth (.01)

lidiya [134]

Answer: Here's the answer hope this helps

Explanation:

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4 years ago

How to unscramble dtneinreigs

torisob [31]

ANSWER: Ingredients.

3 0

3 years ago

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A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of

pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

pH = 10.05

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = 0.20

I hope it helps!

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3 years ago

Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed. 1. H2SO4 + 2NH4OH → ? 2. 2NaOH

sergey [27]

1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O

2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O

3. HNO₃ + KOH ⟶ KNO₃ + H₂O

Explanation:

Acid + base ⟶ salt + water

Take the H from the acid and the OH from the base to get water.

Then, join what’s left to get the salt. Write the symbol for the metal first.

For example, in equation 3, take the H from HNO₃ and the OH from KOH.

Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.

7 0

3 years ago

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