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Andreas93 [3]
3 years ago
15

Which is responsible for carrying the signals for vision from the eye to the brain? retina. rods and cones. optic nerve. cornea​

Chemistry
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

Optic Nerve

Explanation:

lyudmila [28]3 years ago
7 0

<em>Hello There!!</em>

<em>The answer is </em><em>C. </em><em>Optic nerve.</em>

<em>Because, The eye works like a camera. The cells in the retina absorb and convert the light to electrochemical impulses which are transferred along the optic nerve to the brain. The brain is instrumental in helping us see as it translates the image into something we can understand.</em>

<em>P.S </em><em>Tell me if this is wrong...</em>

<em />GoodLuck!!<em />

#Be Bold

<em>#</em> Always Brainly!

_{Loserbrazts}

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Un elemento posee dos isótopos cuyos números de masa suman 68 y la semisuma de sus neutrones es 19. Determine el grupo de este e
katovenus [111]

Answer:

The element belongs to group 15 of the present periodic table

Explanation:

Isotopes have the same proton number, what differs is that they have different number of neutrons.

Now since the half-sum of their neutrons is 19, the total number of neutrons would be 19 * 2 = 38 neutrons.

Also, their masses add up to be 68, since the total mass equals sum of neutrons and sum of protons, this means that the total number of protons is 68-38 = 30

Since this is equal in both isotopes, this means that the proton number of the element is 30/2 = 15

The atomic number is the number of protons in the nucleus of an atom. Since the atomic number is 15, this element is phosphorus and it belongs to group 15 of the present periodic table

5 0
3 years ago
40 POINTS PLEASE HELP
konstantin123 [22]

Answer:

there will be less carbon released through decompostion

and there is less carbon in storage

Explanation:

7 0
3 years ago
What is the correct way to write 340,000,000 in scientific notation?
luda_lava [24]

The answer should be D, it would be 3.4x10(9thpower) because there are nine zeros in 340,000,000.


5 0
4 years ago
The molar heat capacity of ethane is represented in the temperature range 298 K to 400 K by the empirical expression Cp,m in J K
BabaBlast [244]

Answer:

-88.66 kJ/mol

Explanation:

The expressions of heat capacity (Cp,m) for C(s) and for H₂(g) are:

C(s):  Cp,m/(J K-1 mol-1) = 16.86 + (4.77T/10³) - (8.54x10⁵/T²)

H₂(g): Cp,m/(J K-1 mol-1) = 27.28 + (3.26T/10³) + (0.50x10⁵/T²)

Cp = A + BT + CT⁻²

For the Kirchoff's Law:

ΔHf = ΔH°f + \int\limits^{T2}_{T1} {DCp(T)} \, dT

Where ΔH°f is the enthalpy at 298 K, T1 is 298 K, T2 is the temperature given (373 K), and DCp is the variation of Cp (products less reactants). ΔH°f  for ethene is -84.68 kJ/mol and the reaction is:

2C(s) + 3H₂(g) → C₂H₆

So, DCp:

dA = A(C₂H₆) - [2xA(C) + 3xA(H₂)] = 14.73 - [2x16.86 + 3x27.28] = -100.83

dB = B(C₂H₆) - [2xB(C) + 3xB(H₂)] = 0.1272 - [2x4.77x10⁻³ + 3x3.26x10⁻³] = 0.10788

dC = C(C₂H₆) - [2xC(C) + 3xC(H₂)] = 0 - (2x(-8.54x10⁵) + 3x0.50x10⁵) = 15.58x10⁵

dCp = -100.83 + 0.10788T + 15.58x10⁵T⁻²

\int\limits^{373}_{298} {-100.83 + 0.10788T + 15.58x10^5T^{-2}} \, dT = -3796.48 J/mol = -3.80 kJ/mol (solved by a graphic calculator)

ΔHf = -84.68 - 3.80

ΔHf = -88.66 kJ/mol

7 0
3 years ago
A constant volume and mass of helium gas at 77°C is heated so that the pressure of the gas doubles. What is the new temperature
Mariulka [41]

Answer:

427°C .

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial temperature (T1) = 77°C

Initial pressure (P1) = P

Final pressure (P2) = 2P

Final temperature (T2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T (°C) + 273

Initial temperature (T1) = 77°C

Initial temperature (T1) = 77°C+ 273 = 350K

Step 3:

Determination of the new temperature. The new temperature can be obtained as follow:

P1/T1 = P2/T2

P/350 = 2P/T2

Cross multiply

P x T2 = 350 x 2P

Divide both side by P

T2 = (350 x 2P ) / P

T2 = 700K

Step 4:

Conversion of Kelvin temperature to celsius temperature.

This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 700K

T(°C) = 700 – 273

T(°C) = 427°C

Therefore, the new temperature of the gas is 427°C

3 0
4 years ago
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