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Andreas93 [3]
3 years ago
15

Which is responsible for carrying the signals for vision from the eye to the brain? retina. rods and cones. optic nerve. cornea​

Chemistry
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

Optic Nerve

Explanation:

lyudmila [28]3 years ago
7 0

<em>Hello There!!</em>

<em>The answer is </em><em>C. </em><em>Optic nerve.</em>

<em>Because, The eye works like a camera. The cells in the retina absorb and convert the light to electrochemical impulses which are transferred along the optic nerve to the brain. The brain is instrumental in helping us see as it translates the image into something we can understand.</em>

<em>P.S </em><em>Tell me if this is wrong...</em>

<em />GoodLuck!!<em />

#Be Bold

<em>#</em> Always Brainly!

_{Loserbrazts}

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20 Ca :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s²<span>
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Answer D

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4 0
3 years ago
Read 2 more answers
3) List two other names for P-waves and for S-waves.
Dimas [21]
3. Other names for S- waves are secondary waves, shear waves, and sometimes elastic S-waves. Other names for P-waves are primary waves and compressional waves.
4. You need 3 stations, because scientists find the difference between the arrival times of the primary and the secondary waves at each of the 3 stations, then the time difference is used to determine the distance of the epicentre from each station. The greater the difference in time, the further away the epicentre is. A circle is drawn around each station, with a radius corresponding to the epicentre’s distance from that station. The point where the three circles meet is the epicentre. If you only had two stations, you could only predict the epicentre, as the point where all three circles meet wouldn’t be complete, you’d have to try and estimate where the third one would intercept. This would greaten the chance of error and isn’t as accurate.

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5 0
3 years ago
If objects with a greater mass have greater gravitational pull, why is our solar
STatiana [176]

Answer:

It's too far away

Explanation:

According to classical mechanics, gravitational pull is inversely proportional to the distance squared; as the distance increases, the gravitational pull decreases at a faster and faster rate. Since Alpha Centauri A is a few lightyears (Tens of trillions of kilometers away), without even needing to calculate the force of gravity, it is very miniscule.

6 0
3 years ago
How does this splitting wedge make work easier?
nikitadnepr [17]
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7 0
3 years ago
4). One mole of monoclinic sulfur at 25C was placed in a constant-pressure calorimeter whose heat capacity (C) was 1620 J/K. T
andre [41]

<u>Answer:</u> The enthalpy change of the reaction is -243 J/mol

<u>Explanation:</u>

The heat released by the reaction is absorbed by the calorimeter and the solution.

The chemical equation used to calculate the heat released follows:

q=c\times \Delta T

where,

c = heat capacity of calorimeter = 1620 J/K

\Delta T = change in temperature = 0.150^oC=0.150K   (Change remains same)

Putting values in above equation, we get:

q=1620J/K\times 0.15K=243J

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

For the given chemical reaction:

S\text{ (monoclinic)}\rightarrow S\text{ (orthorhombic)}

We are given:

Moles of monoclinic sulfur = 1 mole

  • To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,  

q = amount of heat released = -243 J

n = number of moles = 1 mole

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-243J}{1mol}=-243J/mol

Hence, the enthalpy change of the reaction is -243 J/mol

8 0
3 years ago
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