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babymother [125]

3 years ago

8

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

mass of the wagon, rider, and rock is 93.5 kg. The mass of the rock is 0.310 kg. Initially the wagon is rolling forward at a speed of 0.540 m/s. Then the person throws the rock with a speed of 16.5 m/s. Both speeds are relative to the ground. Find the speed of the wagon after the rock is thrown directly forward.

1 answer:

Lynna [10]3 years ago

7 0

Explanation:

Given Data

Total mass=93.5 kg

Rock mass=0.310 kg

Initially wagon speed=0.540 m/s

rock speed=16.5 m/s

To Find

The speed of the wagon

Solution

As the wagon rolls, momentum is given as

P=mv

where

m is mass

v is speed

put the values

P=93.5kg × 0.540 m/s

P =50.49 kg×m/s

Now we have to find the momentum of rock

momentum of rock = mv

momentum of rock = (0.310kg)×(16.5 m/s)

momentum of rock =5.115 kg×m/s

From the conservation of momentum we can find the wagons momentum So

wagon momentum=50.49 -5.115 = 45.375 kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

Speed of wagon=45.375/(93.5-0.310)

Speed of wagon= 0.487 m/s

Throwing rock backward,

momentum of wagon = 50.49+5.115 = 55.605 kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)

speed of wagon= 0.5967 m/s

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tester [92]

The correct answer to the question is unbalanced .

EXPLANATION:

As per Newton's first laws of motion, we know that a body at rest will be at rest or a body moving with uniform velocity along a straight line will keep on moving with the same velocity along that line unless and until it is compelled by some external unbalanced forces acting on.

Hence, it is the unbalanced force which is responsible for creating the motion on the body.

As per the question, Anne applied some force on the toy car. It is called applied force. There is also frictional force between car and the surface which opposes the motion of the car. The toy car will move due to the net force acting on it. The net force is known as unbalanced force.

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4 years ago

Read 2 more answers

A sound wave travels twice as far in neon (Ne) as it does it krypton (Kr) in the same time interval. Both neon and krypton can b

avanturin [10]

Answer:

281.6 K

Explanation:

The speed of sound in an ideal gas is given by c = √(γKT/m).

From the question speed of sound in Ne, c₁ = 2c₂ speed of sound in Kr

c₁ = √(γKT₁/m₁) and c₂ = √(γKT₂/m₂)

So √(γKT₁/m₁) = 2√(γKT₂/m₂) where T₁, m₁ and T₂, m₂ are the temperatures and atomic masses of Neon and Krypton respectively.

So, √(T₁/m₁) = 2√(T₂/m₂)

(T₁/m₁) = 4(T₂/m₂) (squaring both sides)

T₁ = 4(T₂m₁/m₂)

Given that m₁ = 20.2 u , m₂ = 83.8 u, T₂ = 292 K

T₁ = 4(292 × 20.2/83.8) K = 23593.6/83.8 = 281.55 K ≅ 281.6 K

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3 years ago

Amanda [17]

Answer:

When a particle or a system of particles move in a system where no external force acts, then the total linear momentum of the particle system remains constant.

Explanation:

Given data:

Total mass of the skateboarder, $m_{1} = 70 \ kg$

Mass of the friend, $m_{2} = 50 \ kg$

Initial velocity of the skateboarder, $u_{1} = 3 \ m/s$

Initial velocity of the the friend, $u_{2} = 0$

Let the new velocity of the skateboarder when his friend jumps be $v$ .

From the conservation law of linear momentum,

$m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v$

$70 \times 3 + 50 \times 0 = (70 + 50)v$

$\Rightarrow \ v &= 1.75 \ m/s.$

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Answer:

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3 years ago

A 0.040kg block of of copper at 95℃ is placed in 0.105kg of water at an unknown temperature. After equilibrium is reached, the f

Rainbow [258]

Answer:

Explanation:

heat lost by block of copper

= mass x specific heat x fall in temperature

= .04 x 385 x ( 95 - 24 )

= 1093.4 J

Heat gained by water

= .105 x 4200 x ( 24 - T ) ; Here T is initial temperature of water .

= 441 ( 24 - T )

heat lost = heat gained

1093.4 = 441 ( 24 - T )

24 - T = 2.48

T = 21.52 ℃

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3 years ago