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babymother [125]
3 years ago
8

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

mass of the wagon, rider, and rock is 93.5 kg. The mass of the rock is 0.310 kg. Initially the wagon is rolling forward at a speed of 0.540 m/s. Then the person throws the rock with a speed of 16.5 m/s. Both speeds are relative to the ground. Find the speed of the wagon after the rock is thrown directly forward.
Physics
1 answer:
Lynna [10]3 years ago
7 0

Explanation:

Given Data

Total mass=93.5 kg

Rock mass=0.310 kg

Initially wagon speed=0.540 m/s

rock speed=16.5 m/s

To Find

The speed of the wagon

Solution

As the wagon rolls, momentum is given as

P=mv

where

m is mass

v is speed

put the values

P=93.5kg × 0.540 m/s

P =50.49 kg×m/s

Now we have to find the momentum of rock

momentum of rock = mv

momentum of rock = (0.310kg)×(16.5 m/s)

momentum of rock =5.115 kg×m/s  

From the conservation of momentum we can find the wagons momentum So

wagon momentum=50.49 -5.115 = 45.375 kg×m/s  

Speed of wagon = wagon momentum/(total mass-rock mass)

Speed of wagon=45.375/(93.5-0.310)

Speed of wagon= 0.487 m/s

Throwing rock backward,

momentum of wagon = 50.49+5.115 = 55.605  kg×m/s

Speed of wagon = wagon momentum/(total mass-rock mass)

speed of wagon = 55.605  kg×m/s/(93.5kg-0.310kg)

speed of wagon= 0.5967 m/s

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Answer:

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Explanation:

Applying,

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But,

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From the question,

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3 years ago
To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

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Constant electric field, E = 343 N/C

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Here a is acceleration.

From equation (1) and (2).

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a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }

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(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

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Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

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insens350 [35]

Answer:

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