Based on the 95% confidence interval, the conclusion would be that the whale-watching company has a 95% chance of seeing between -.507 and 1.307 whales on any given day.
<h3>Why can this conclusion be drawn?</h3>
The test was to find out how many whales could be seen on a given day and this was tested at a 95% significance level.
The 95% confidence interval was shown to be (-0.507, 1.307). This means that there is a 95% chance that between -0.507 and 1.307 whales will be seen on a given day.
Find out more on confidence intervals at brainly.com/question/26267323.
Answer:
The horizontal velocity is constant at 16 m/s.
After 1 sec since v = a t then 9.8 m/s^2 * 1 sec = 9.8 m/s for the vertical velocity
V = (Vx^2 + Vy^2)^1/2 = (16^2 + 9.8^2)^1/2 = 18.8 m/s
Answer:
d)symmetry
Explanation:
Here is the complete question
In deriving the axial electric field for the ring-shaped charge distribution and the electric field from a long line of charge, the component perpendicular to the resulting field is zero because of what physical property? Answer a)integration b)superposition c)only net charge is important d)symmetry e) positive and negative charges cancel
Solution
The perpendicular components of the resulting electric field is zero because of symmetry since the charge is evenly distributed around the ring or line of charge. At one point, there is an electric field dE due to a small charge element dq and a corresponding electric field dE' due to a small charge element dq' opposite to dq.
Since the charges are symmetrical about the center, the horizontal (or perpendicular) components of the electric fields would cancel out causing the horizontal component of the resulting electric field to be zero.
So, the perpendicular component of the resulting electric field is zero due to symmetry.
Answer:
p = -8 kg-m/s
Explanation:
Given that,
Initial speed of the rock, u = 8 m/s
Mass of the rock, m = 1 kg
The ball travels up to a maximum height, then returns to the ground.
We need to find the rock's momentum as it strikes the ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So
p = mv
p = 1 kg × (-8 m/s)
= -8 kg-m/s
So, the rock's momentum as it strikes the ground is (-8 kg-m/s).