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liraira [26]
3 years ago
11

The velocity of a particle traveling along a straight line is v = Vo − ks where k is constant. If s=0 when t=0, determine the po

sition and acceleration of the particle as a function of time.
Physics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

acceleration of the particle as a function of time is given as

a(t)=-\frac{ks}{t}

and position of the particle as a function of time is given as

x(t)=ut+\frac{at^2}{2} \\x(t)=V_{0}t-\frac{\frac{ks(t)}{t}t^2}{2}

x(t)=V_{0}t-\frac{kst}{2}

Explanation:

we have given,

v=v_{o}− ks

at t=0, s=0

therefore initial velocity,u

u=v=V_{o}

v=u+at.........(1)

we know from first equation of motion

let acceleration at time t be a(t), and position be x(t)

put value of v,u and a in equation 1

we got,

V_{o}-ks=V_{o}+a(t)t

Therefore,acceleration of the particle as a function of time is given as

a(t)=-\frac{ks}{t}

and position of the particle as a function of time is given as

x(t)=ut+\frac{at^2}{2} \\x(t)=V_{0}t-\frac{\frac{ks}{t}t^2}{2}

x(t)=V_{0}t-\frac{kst}{2}

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While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential
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Answer:

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