Answer:
The magnitude of the electric field is
Explanation:
Given:
Charge of electron C
Separation between two charges m
For finding the magnitude of the electric field,
Where
Therefore, the magnitude of the electric field is
Answer:
161.938 Hz
Explanation:
the computation of the fundamental resonant frequency is shown below
p = 1100 kg/m^3
A = 130 mm^2
= 130 ×10^-6 m^2
T = 600 N
L = 20 cm
= 0.2 m
Now the linear density of tendon is
= 1100 kg/m^3 × 130 ×10^-6
= 0.143 kg/m
Now the wave of the string is
= √600 ÷ √0.143
= 64.775 m/s
Now finally the fundamental resonant frequency is
= 64.775 ÷ (2 × 0.2)
=161.938 Hz
We will first record its mass and then its volume by measuring its dimensions
then divide mass by volume and will get density of regular solid
F = kq1q2/r²
F = 9.0(10^9)(10)(50)/20²
F = 1.125 * 10^10 N