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madreJ [45]
3 years ago
9

How can density be determined in a lab of a rectangular solid?

Physics
1 answer:
True [87]3 years ago
6 0
We will first record its mass and then its volume by measuring its dimensions
then divide mass by volume and will get density of regular solid
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Sun is the main source of energy
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a student is pushing a 50 kilogram cart with a force of 500 newtons another students measures the speed of the cart and finds th
Irina-Kira [14]

The force of friction is 300 N

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

\sum F = ma

where

\sum F is the net force acting on the object

m is its mass

a is its acceleration

For the cart in this problem, we have two forces acting on it:

- The force of push, F = 500 N, forward

- The force of friction, F_f, backward

So Newton's second law can be rewritten as

F-F_f = ma

where

m = 50 kg

a=4 m/s^2 is the acceleration of the cart

And solving for F_f, we find the force of friction:

F_f = F-ma=500-(50)(4)=300 N

Learn more about force of friction:

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4 0
3 years ago
(3)science who ever gets this right will get a brainlest
lara [203]

Answer:

True.

Explanation:

It also affects your lungs by getting lung disease.

3 0
3 years ago
Determine the index of refraction of glass that is struck by unpolarized light at 53.8 degrees and resulting in a fully polarize
nignag [31]

Answer:

The refractive index of glass, \mu_{g} = 1.367

Solution:

Brewster angle is the special case of incident angle that causes the reflected and refracted rays to be perpendicular to each other or that angle of incident which causes the complete polarization of the reflected ray.

To determine the refractive index of glass:

tan\theta_{P} = \frac{\mu_{g}}{\mu_{a}}                 (1)

where

\mu_{a} = refractive index of glass

\mu_{g} = refractive index of glass

Now, using eqn (1)

tan{53.8^{\circ}} = \frac{\mu_{g}}{1}

\mu_{g} = tan53.8^{\circ}

\mu_{g} = 1.367

5 0
3 years ago
Vector B has x, y, and z components of 2.4,
Fed [463]

The magnitude of the vector B is 10.9

A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.

To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.

Vector B has components,

x = 2.4

y = 9.8

z = 4.1

Applying the formula,

|B| = √x²+y²+z²

|B| = √(2.4)² + (9.8)² + (4.1)²

|B| = √5.76+96.04+16.81

|B| = √118.61

|B| = 10.9

Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)

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