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NemiM [27]
3 years ago
11

Which of the following is not the same as 2.97 milligrams?

Chemistry
2 answers:
Len [333]3 years ago
5 0
Hi There!!!!!!

Which of the following is not the same as 2.97 milligrams?A)0.297 cg
B)0.00297 g
C) 0.0000297 KG

Answer:0.00297 g

Evgesh-ka [11]3 years ago
3 0

Answer : The (C) 0.0000297 kg is not the same as 2.97 mg.

Explanation :

The conversion used for mass from milligram to centigram is:

1mg=10^{-1}cg

The conversion used for mass from milligram to gram is:

1mg=10^{-3}g

The conversion used for mass from milligram to kilogram is:

1mg=10^{-6}kg

As we are given that the mass 2.97 mg. Now we have to determine the mass in cg, g and kg.

Mass of 'cg' :

1mg=10^{-1}cg

2.97mg=\frac{2.97mg}{1mg}\times 10^{-1}cg=2.97\times 10^{-1}cg=0.297cg

Mass of 'g' :

1mg=10^{-3}g

2.97mg=\frac{2.97mg}{1mg}\times 10^{-3}g=2.97\times 10^{-3}g=0.00297g

Mass of 'kg' :

1mg=10^{-6}kg

2.97mg=\frac{2.97mg}{1mg}\times 10^{-6}kg=2.97\times 10^{-6}kg=0.00000297kg

Hence, from this we conclude that, 0.0000297 kg is not the same as 2.97 mg.

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<u>Answer:</u> The mass percent of calcium in milk is 0.107 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

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Putting values in equation 1, we get:

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The given chemical equation follows:

Na_2C_2O_4(aq.)+Ca^{2+}(aq.)\rightarrow CaC_2O_4(s)+2Na^+(aq.)

Sodium oxalate is present in excess. So, it is considered as an excess reagent. And, calcium ion is a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of calcium oxalate is produced from 1 mole of calcium ion

So, 0.0033 moles of calcium oxalate is produced from = \frac{1}{1}\times 0.0033=0.0033mol of calcium ions

  • Now, calculating the mass of calcium ions by using equation 1, we get:

Moles of calcium ions = 0.0033 moles  

Molar mass of calcium ions = 40 g/mol

Putting values in equation 1, we get:

0.0033mol=\frac{\text{Mass of calcium ions}}{40g/mol}\\\\\text{Mass of calcium ions}=(0.0033mol\times 40g/mol)=0.132g

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\text{Mass percent of calcium ions}=\frac{\text{Mass of calcium ions}}{\text{Mass of milk}}\times 100

Mass of milk = 125 g

Mass of calcium ions = 0.132 g

Putting values in above equation, we get:

\text{Mass percent of calcium ions}=\frac{0.132g}{125g}\times 100=0.107\%

Hence, the mass percent of calcium in milk is 0.107 %

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