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3 years ago

A soccer player kicks a ball with 20 Newtons of force causing it to travel 100 meters. How much work is done on the ball?

Physics

2 answers:

Rzqust [24]3 years ago

7 0

Answer: 2000j

Explanation:

Got it right in a quizziz!

Paraphin [41]3 years ago

3 0

Answer:

2000j

Explanation:

Please make brainliest....i took the quiz

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An ac generator has a frequency of 5.0 kHz and a voltage of 45 V. When an inductor is connected between the terminals of this ge

Ierofanga [76]

Answer:

Explanation:

Given that,

Frequency f = 5 kHz = 5000Hz

Voltage V=45V

Current In inductor I = 65mA

I = 65 × 10^-3 = 0.065A

We want to find inductance L

We know that the reactive inductance cam be given as

XL = 2πFL

Where

XL is reactive inductance

F is frequency

L is inductance

Then,

L = XL/2πF

From ohms law

V = IR

We can calculate the receive reactance of the inductor

V = I•XL

Then, XL = V/I

XL = 45/0.065

XL = 692.31 ohms

Then,

L = XL/2πF

L = 692.31/(2π×5000)

L = 0.02204 H

Then, L = 22.04 mH

The inductance of the inductor is 22.04mH

4 0

3 years ago

Read 2 more answers

An alpha particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference

kondor19780726 [428]

Answer:

a) v = 1.075*10^7 m/s

b) FB = 7.57*10^-12 N

c) r = 10.1 cm

Explanation:

(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:

$K=qV$ (1)

q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C

V: potential difference = 1.2*10^6 V

You replace the values of the parameters in the equation (1):

$K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J$

The kinetic energy of the particle is also:

$K=\frac{1}{2}mv^2$ (2)

m: mass of the particle = 6.64*10^⁻27 kg

You solve the last equation for v:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}$

the sped of the alpha particle is 1.075*10^6 m/s

b) The magnetic force on the particle is given by:

$|F_B|=qvBsin(\theta)$

B: magnitude of the magnetic field = 2.2 T

The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1

$|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N$

the force exerted by the magnetic field on the particle is 7.57*10^-12 N

c) The particle describes a circumference with a radius given by:

$r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm$

the radius of the trajectory of the electron is 10.1 cm

6 0

4 years ago

How is wave movement affected by the various mediums it may travel through?

Juliette [100K]

Answer:

speed is affected by the medium in wich the wave travels.

Explanation:

The speed of a wave is affected when traveling in different medium, depending on the medium in which the wave travels it can go faster or slower, or not even be able to travel in that medium.

For light waves, the denser the medium through which the wave travels, the slower it will go through it, as there is more resistance to the light particles.

And in waves like sound, which instead of particles is a vibration or disturbance in the medium, they travel faster in denser mediums such as metal, because the disturbance is transmitted more efficiently thanks to how close together that the particles are in the metal, This is why sound does not travel in a vacuum; there are not even particles to transmit the vibration.

5 0

3 years ago

How can technology improve peoples chances of surviving a tornado?

BigorU [14]

Answer:

Explanation:

The warning would alert the people and give them time to prepare for the tornado. like getting food and going in bunkers

Brainliest awnser?

8 0

3 years ago

An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if

maxonik [38]

The electron is accelerated through a potential difference of $\Delta V=780 V$ , so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
$\frac{1}{2}mv^2 = e \Delta V$
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
$\Delta V$ is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
$v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s$

Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
$evB=m \frac{v^2}{r}$
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
$B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T$

3 0

4 years ago