Answer:
0.022 H
Explanation:
From Alternating current,
V = (XL)I..................... Equation 1
Where V = Voltage of the generator, I = current in the inductor, XL = Inductive reactance of the generator.
Make XL the subject of the equation
XL = V/I................. Equation 2
Given: V = 45 V, I = 65 mA = 0.065 A
Substitute into equation 2
XL = 45/0.065
XL = 692.31 Ω
But,
XL = 2πFL........................ Equation 3
Where F = frequency of the generator, L = Inductance of the inductor
Make L the subject of the equation
L = XL/(2πF).................. Equation 4
Given: F = 5.0 kHz = 5000 Hz, π = 3.14, XL = 692.31 Ω
L = 692.31/(2×3.14×5000)
L = 0.022 H
