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Vinvika [58]
3 years ago
7

A yodeler yodels at a cliff 2000 m away. The sound of the echo returns in 9.8 s. If the wavelength of the sound wave is .85 m th

en what is the period of the sound wave?
Physics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

Hey man, are you who I think you are? ... you used your student number on your account.... anyways im in your class :) guess who I am for free points. so the formula for period is Period=Wavelength/Velocity, so P=.85/velocity, to find velocity would be using the formula speed=distance/time, so the velocity is 2000/9.8 which is around 204.0816327.... so back to period formula, P=.85m/204.08 which gives a period of .004165. But im not entire sure so you have to check that on your own. (gl guessing who I am. hehe)

Explanation:

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The liquid that will evaporate the quickest would be water. 
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A 1.0 m string with a 5 g stopper on the end is whirled in a vertical circle. The speed of the stopper is 8 m/s at the top of th
Andrew [12]

Answer:

Explanation:

A )

At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy

1/2 m V² = mg x 2r + 1/2 mv²

m is mass of stopper , V is velocity at the bottom , r is radius of the circular path which is length of the string , v is velocity at the top

1/2  V² = g x 2r + 1/2 v²

 V² = g x 4r +  v²

 V² = 9.8 x 4 +  8²

V² = 103.2

V = 10.16 m/s

B )

If T be the tension at the top

Net downward force

= mg + T . This force provides centripetal force for the circular motion

mg +T = mv² / r

T =   mv²/r -mg

= m ( v²/r - g )

= .005 ( 8²/1 -g )

= .005 x 54.2

= .27 N .

C ) At the bottom

Net force = T  - mg , T is tension at the bottom , V is velocity at bottom

T-mg = mV²/r

T = m ( V²/r +g )

= .005 ( 10.16²/1 +9.8)

= .005 x 113

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3 0
3 years ago
The figure above shows 4forces 3N, 10N, 3√3N, and 6N acting on a particle P. The resultant of the four forces is.
Brilliant_brown [7]

As you gave no pic I took them on one lined

  • F_1=3N
  • F_2=10N
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\\ \sf\longmapsto F_{net}=F_1+F_2\dots

\\ \sf\longmapsto F_{net}=3+10+6+3\sqrt{3}

\\ \sf\longmapsto F_{net}=19+3(1.732)

\\ \sf\longmapsto F_{net}=19+5.196

\\ \sf\longmapsto F_{net}=24.196N

6 0
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How do radios work?
ycow [4]

Answer:

radios work when electrons are speeding up and dow the attena, patters structure and shape make music pleasing to hear. (more info below)

Explanation:

a radio works when electrons are speeding up and down the antenna, sending out electromagnetic waves. Radiation waves travel through the air at the speed of light. When the radio waves reach the antenna, the electrons vibrate within the antenna and reproduce the initial signal. to make music pleasing to hear it has to have patterns, structure, shape.

hope this helped!

6 0
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