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Papessa [141]
4 years ago
13

What is the total number of atoms in 1.0 mole of

Chemistry
1 answer:
emmainna [20.7K]4 years ago
6 0

D. 18 x 10^23 is the total number of atoms in 1.0 mole of CO2
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Vedmedyk [2.9K]
I believe the correct answers from the choices listed above is option B and D. The type of substances that would classify salt water would be homogeneous mixture and a solution. Salt water has uniform properties all through out. Hope this answers the question.
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3 years ago
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The domain Archaea are unicellular prokaryotes and can be autotrophs or heterotrophs
nexus9112 [7]

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Explanation:

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3 years ago
SOMEONE PLEASE HELP ME WILL MARK BRAINLIEST PLEASE!!
QveST [7]

O₂ required = 1/2 x 7.8 = 3.9 moles

7 0
2 years ago
What is the volume of 40.0 grams of argon gas at STP ?
MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Aqueous Solutions</u>

  • States of Matter

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 40.0 g Ar

[Solve] L Ar

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 24.9235 \ L \ Ar

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

24.9235 L Ar ≈ 24.9 L Ar

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3 years ago
Add 2 protons to carbon what element do you create
victus00 [196]
It will become oxygen because carbons atomic number is 6 which means it has 6 protons so when you add 2 more protons you will have 8 all together and oxygens atomic number is 8 which is 8 protons
6 0
3 years ago
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