I believe the correct answers from the choices listed above is option B and D. The type of substances that would classify salt water would be homogeneous mixture and a solution. Salt water has uniform properties all through out. Hope this answers the question.
Answer:
I think its true I dont really know
Explanation:
true
O₂ required = 1/2 x 7.8 = 3.9 moles
Answer:
24.9 L Ar
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Aqueous Solutions</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 40.0 g Ar
[Solve] L Ar
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Ar - 39.95 g/mol
[STP] 22.4 L = 1 mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
24.9235 L Ar ≈ 24.9 L Ar
It will become oxygen because carbons atomic number is 6 which means it has 6 protons so when you add 2 more protons you will have 8 all together and oxygens atomic number is 8 which is 8 protons