Answer:
<em>The primary coil has 13,400 turns</em>
Explanation:
<u>Voltage Transformers</u>
A transformer is an electrical apparatus that converts an alternating electrical voltage to another. Step-down transformers lower the voltage from higher levels (kilovolts) to consumer levels (120/240 Volts).
The ratio between both voltages can be computed as
Where V1 is the primary voltage and V2 is the secondary voltage. This ratio depends on the turns ratio of the coils wounded in a common magnetic core.
Being N1 the number of turns of the coils of the primary side and N2 the number of turns in the secondary coil. Both relations give us
Solving for N1
We have:
Calculate N1
The primary coil has 13,400 turns
What you can use is coulomb's inverse square law that states that force varies inversly as the square of distance. <span>It menas that the force is calculated by dividing by distance squared. what this does is essentially as the distance doubles, the forces is reduced by a factor of 4 or can be divided by 4. Force at 0.5m=2.3328N. And brings you ti the answer</span>
for example
1. drinking water at least after 1 hour beacuse if we immediately drink water just after meal it dilutes the HCL produced in our stomach which hinders the digestion process
2.picking up tomatoes for salads which contains oxalic acid
3.Cutting apples which contains malic acid with knife then after sometimes it will trun into brown due to oxidation of iron present in a apple.
Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)
• The net force in the parallel direction is
∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
• The net force in the perpendicular direction is
∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0
Solving the second equation for <em>n</em> gives
<em>n</em> = <em>mg</em> cos(21°)
<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)
<em>n</em> ≈ 1.83 N
Then the magnitude of friction is
<em>f</em> = <em>µn</em>
<em>f</em> = 0.25 (1.83 N)
<em>f</em> ≈ 0.457 N
Solve for the acceleration <em>a</em> :
-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)
<em>a</em> ≈ -5.80 m/s²
so the block is decelerating with magnitude
<em>a</em> = 5.80 m/s²
down the ramp.
