Answer:
is destroy.
Explanation:
Because it is one of the demerit of a machine
In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of
(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s
Answer:
5.77×10¹⁰ m
Explanation:
From the question,
Applying
Kepler's third law
P² = d³...................... Equation 1
Where P = Planet's period, d = distance between the center of the planet and the sun.
make d the subject of the formula n equation 1
d = ![\sqrt[3]{P^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BP%5E%7B2%7D%20%20%7D)
.................. Equation 2
Given: P = 0.24 sidereal.
Substitute the value of P into equation 2
d = ![\sqrt[3]{0.24^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.24%5E%7B2%7D%20%7D)
d = 0.386 Au
d = 0.386×1.496×10¹¹
d = 5.77×10¹⁰ m
The assume that goes with the inquiry demonstrates the wavelenghts of the photons transmitted by Balmer arrangement change , from vitality levels (n) 3, 4, 5, and 6 to the vitality level (n) 2, in hydrogen particles.
These are the values shown in the figure
Transition wavelength of the photon emitted
nm
from n=3 to n=2 656<------ this is the value requested
from n=4 to n=2 486
from n=5 to n=2 434
from n=6 to n=2 410
The wavelength of a photon discharged from the n = 3 shell in hydrogen is the primary information of the table, i.e 656 nm.
Using the conversion factor from nm to m that results is :
656 nm * 1 m / (10^9 nm) = 656 * 10 ^ -9 m.
Hope this helps
2nd stone time = 13.0/9.8 = 1.33 seconds
distance = 0.5*9.8*1.33^2 = 8.67 meters
1st stone time = 1.33+1.5 = 2.83 seconds
distance = 0.5*9.8*2.83^2 = 39.24 meters
39.24-8.67 = 30.57 meters apart
