The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
<h3>What is normal force?</h3>
The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.
This force is applied by the solid bodies on each other in order to prevent the passing through each other.
A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.
- The body is gaining the speed, which means there is a change in kinetic energy.
- The change in kinetic energy is equal to the work done.
- The friction force is the product of coefficient of the friction and normal force.
- The friction force for the given case is zero. Thus, the normal force must be equal to the zero.
Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.
Learn more about the normal force here;
brainly.com/question/10941832
Beat frequency, fb = |f2-f1|
That is, beat frequency is the absolute difference between two frequencies. Is is as a results of destructive and constructive inferences.
Therefore, in this case:
fb = 203 - 199 = 4 Hz
The chemical bonds alow it to pass to the other object.
To find the relative frequencies, divide each frequency by the total number of throws - in this case, 100.
Red: 10/100=1/10=0.1
Yellow:35/100=0.35
Blue:48/100= 0.48
Misses: 7/100=0.07
The event of landing in the red region has a relative frequency of 0.1 which means the dart landed in the red region about 10% (0.1 x 100%) of the time.
Answer:
The equilibrium points include
x₁ = - 1.177
x₂ = 0
x₃ = 1.177
Explanation:
At equilibrium, the sum of forces acting on a body is equal to zero.
F(x) = ax (b − cx²) [a = 8.97, b = 7.83, c = 5.65]
F(x) = (abx - acx³)
= (8.97×7.83)x - (8.97×5.65)x³
F(x) = 70.2351x - 50.6805x³
At equilibrium, F(x) = 0
70.2351x - 50.6805x³ = 0
x(70.2351 - 50.6805x²) = 0
x = 0 or (70.2351 - 50.6805x²) = 0
70.2351 - 50.6805x² = 0
50.6805x² = 70.2351
x² = (70.2351/50.6805)
x² = 1.385840708
x = ± 1.177
So, x = -1.177, 0 and 1.177
x₁ = - 1.177
x₂ = 0
x₃ = 1.177
Hope this Helps!!!