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Vladimir [108]
3 years ago
12

Radium-226 emits alpha (α), beta (β) and gamma (γ) radiation.

Physics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

Explanation:

alpha

Alpha Radiation (α): A large, unstable nucleus decays to produce a smaller, more stable nucleus and an alpha particle (identical to a helium nucleus, ⁴₂He or ⁴₂α).

It has a very high ionizing energy and low penetrating power. It can be stopped by paper skin

Beta Radiation (β): A neutron in an unstable nucleus decays, forming a proton and emitting a beta (β) particle (identical to an electron, ⁰₋₁e or ⁰₋₁b) and resulting in a more stable nucleus.

It has high ionizing energy and penetrating power. It can be stopped by aluminium sheet

Gamma Radiation (γ): An unstable nucleus releases energy in the form of a high energy photon (no mass)to become more stable; this often accompanies other forms of radioactivity.

It has very high penetrating power and very low ionizing energy. It can be stopped by lead block.

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The __________ association area is responsible for perceiving and attending to stimuli, and the __________ association area is r
AlladinOne [14]

Answer:

Parietal on the first blank and temporal on the second

4 0
3 years ago
An inclined plane is used to lift a box into a moving truck. The ramp is 6m long and 1.5m
ElenaW [278]

Given :

An inclined plane is used to lift a box into a moving truck. The ramp is 6 m long and 1.5 m.

To Find :

The mechanical advantage of the inclined plane.

Solution :

Mechanical advantage, M.A of an inclined plane is given by :

M.A = \dfrac{\text{Length of slope}}{\text{Height of plane}}

Putting given values in above equation, we get :

M.A = \dfrac{6 \ m}{1.5 \ m}\\\\M.A = 4

Therefore, the mechanical advantage of the inclined plane is 4.

5 0
3 years ago
A voltaic cell with an aqueous electrolyte is based on the reaction between Cd2+(aq) and Mg(s), producing Cd(s) and Mg2+(aq). Wr
Monica [59]

Answer : The balanced two-half reactions will be,

Oxidation half reaction (anode) : Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

Reduction half reaction (cathode) : Cd^{2+}(aq)+2e^-\rightarrow Cd(s)

Thus the overall reaction will be,

Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

The given redox reaction occurs between the magnesium and cadmium.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

Oxidation half reaction (anode) : Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

Reduction half reaction (cathode) : Cd^{2+}(aq)+2e^-\rightarrow Cd(s)

Thus the overall reaction will be,

Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)

4 0
3 years ago
Read 2 more answers
PLEASE HELP IVE BEEN STUCK ON THIS FOR 3HOURS!
Anika [276]

Answer:

The river bank can expand due to the water breaking apart which can cause sediment to move and change/erode

5 0
3 years ago
A ring with an 18mm diameter falls off a scientist's finger into the solenoid in the lab. The solenoid is 25 cm long, 5.0 cm in
Troyanec [42]

Answer:

The value is  \epsilon =  3.84 *10^{-5} \  V

Explanation:

From the question we are told that

  The diameter of the ring is  d =  18 \ mm  =  0.018 \  m

   The length of the solenoid is l = 25 \ cm  =  0.25 \ m

   The diameter of the solenoid is  D = 5.0 \ cm  = 0.05 \ m

    The number of turns is  N = 1500

   The change in  current in the solenoid is   \Delta  I   = 20 \ A

   The time taken is  \Delta  t  = 1 \ s

Generally the radius of the ring is  

     r = \frac{d}{2}

=>  r = \frac{0.018 }{2}

=>  r = 0.009 \ m

Generally the area of the ring is mathematically represented as  

      A = \pi r^2

=>   A = 3.142 *  0.009^2    

=>   A = 2.545 *10^{-4}\ m^2

Generally the induced emf is mathematically represented as

       \epsilon  =  A * \frac{dB}{dt}

Here    

         \frac{dB }{dt} =  \mu_o * \frac{N}{l} *\frac{ \Delta I }{\Delta t}

Here  \mu_o is the permeability of free space with value  

         \mu_o =  4\pi *10^{-7} \ N/A^2

So  

     \frac{dB }{dt} =   4\pi * 10^{-7} * \frac{1500}{0.25} *\frac{20 }{1}

=>  \frac{dB }{dt} =   0.150816\  T/s

So

     \epsilon =   0.150816 *  2.545 *10^{-4}

=>   \epsilon =  3.84 *10^{-5} \  V

3 0
2 years ago
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