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4 years ago

If the distance between the two objects is reduced in half, what will be the changed force of attraction between them?

Physics

1 answer:

NNADVOKAT [17]4 years ago

8 0

Will reduce 4 times.

$F = G \frac{m1* m2}{ d^{2} }$
So called LUG (Law of Universal gravitation).

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That's called "refraction".

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How could the man in the image better improve his posture?

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Answer:

Explanation:

if you sit up straight you will have a proper posture

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Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista

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Answer:

$v = 7793150 m/s$

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

$v = \frac{kQ}{r}$

Where $k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }$

and it is satisfy the superposition principle, thus

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}$

$v = 222.73v$

The electrical potential at 10 cm from charge 1 is:

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}$

$v = 395.44 v$

Since the work - energy theorem, we have:

$q\Delta v = \frac{mv^{2} }{2}$

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Therefore:

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$v = 7793150 m/s$

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3 years ago

While playing her guitar , karen plucks one string with increasing levels of force. What effect does this have on the sound prod

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Answer:

The amplitude of vibration of string will increase due to which loudness of sound will increase

Explanation:

As we know that the guitar is based on the principle of Resonance. When string of the guitar vibrates at a given frequency then the sound produced in the hollow part of the guitar will also be at same frequency.

This is known as resonance condition, so guitar will produce same frequency sound as that of frequency of string.

Now if the string is plucked with increasing level of force then it will increase the amplitude of vibrations of the string due to which the sound produced in the guitar will also be of same level.

So here we can say that amplitude and intensity of sound related as

$I = kA^2$

so on increasing amplitude the intensity will increase and hence it will produce loud sound

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3 years ago

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A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15°, and rolls to the bottom. The

cluponka [151]

Answer:

v = 4.1 m/s

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As per mechanical energy conservation law we can say that initial total gravitational potential energy of the sphere is equal to final kinetic energy of rolling

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