Answer:
Explanation:
Given that 
g=9.8m/s²
The spring constant is 
k=50N/m
The length of the bungee cord is 
Lo=32m
Height of bridge which one end of the bungee is tied is 91m
A steel ball of mass 92kg is attached to the other end of the bungee. 
The potential energy(Us) of the steel ball before dropped from the bridge is given as
P.E= mgh
P.E= 92×9.8×91
P.E= 82045.6 J
Us= 82045.6 J
Potential energy)(Uc) of the cord is given as
Uc= ½ke²
Where 'e' is the extension
Then the extension is final height extended by cord minus height of cord
e=hf - hi
e=hf - 32
Uc= ½×50×(hf-32)²
Uc=25(hf-32)²
Using conservation of energy,
Then,
The potential energy of free fall equals the potential energy in string
Uc=Us
25(hf-32)²=82045.6
(hf-32)² = 82045.6/25
(hf-32)²=3281.825
Take square root of both sides
√(hf-32)²=√(3281.825)
hf-32=57.29
hf=57.29+32
hf=89.29m
We neglect the negative sign of the root because the string cannot compressed 
 
        
             
        
        
        
The speed of the second satellite is less than the speed of the first satellite.
<h3>What is speed?</h3>
The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Given is a satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther away from the same planet. 
When the distance from the center of the orbit increases, the time to complete the orbit will be greater.
Thus, the speed of the second satellite is less than the speed of the first satellite.
Learn more about speed.
brainly.com/question/7359669
#SPJ1
 
        
             
        
        
        
Answer:
Twice
Explanation:
From the formula for velocity in a circle
V= 2πr/T 
Where V is velocity
 r is raduis 
 T is period
We see that as r increases V increases so if r is doubled V becomes doubled
 
        
             
        
        
        
Complete Question
The speed of a transverse wave on a string of length L and mass m under T is given by the formula
      
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Answer:

Explanation:
From the question we are told that
Speed of a transverse wave given by
 
Maximum Tension is 
Generally making  subject from the equation mathematically we have
 subject from the equation mathematically we have




Therefore the Linear mass in terms of Velocity is given by

 
        
             
        
        
        
Aw don’t say that! I’m sure your beautiful:)