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Zina [86]
3 years ago
5

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x= 5.0 cos

(2t + 3.1416/6 Where x is in centimeter and t is seconds. At t=0, Find a) the position of the particle b) its angular velocity and frequency c)its acceleration d)The period e)the amplitude of the motion
Physics
1 answer:
lakkis [162]3 years ago
3 0

Answer:

a)   x = 4.33 m ,   b)  w = 2 rad / s ,  f = 0.318 Hz ,  c) a = - 17.31 cm / s²,  

d) T =  3.15 s,  e)  A = 5.0 cm

Explanation:

In this exercise on simple harmonic motion we are given the expression for motion

          x = 5 cos (2t + π / 6)

they ask us for t = 0

a) the position of the particle

      x = 5 cos (π / 6)

      x = 4.33 m

remember angles are in radians

 

b) The general form of the equation is

          x = A cos (w t + Ф)

when comparing the two equations

         w = 2 rad / s

angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 2 / 2pi

           f = 0.318 Hz

c) the acceleration is defined by

      a == d²x / dt²

      a = - A w² cos (wt + Ф)

for t = 0 ,  we substitute

      a = - 5,0 2² cos (π / 6)

      a = - 17.31 cm / s²

d) El period is

          T = 1/f

         T= 1/0.318

         T =  3.15 s

e) the amplitude

        A = 5.0 cm

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Shearing stress = u×V.terminal/h = 0.86×V/0.0002

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A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find
pshichka [43]

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In this problem, we have:

I=1.41 A (current in the wire)

B=5.61\mu T=5.61\cdot 10^{-6} T (strength of magnetic field)

Solving  for r, we find the distance  from the wire:

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A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
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Answer:

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\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

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If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

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Ugo [173]

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Explanation:

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F = ma

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7 0
3 years ago
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