If r1 < r2 < r3, and if these resistors are connected in series in a circuit, which one dissipates the most power
1 answer:
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Answer:
Explanation:
the integral for the work is:
the work is against the gravitational force. While the coal is going up, M(y) is changing due to the length of the cable is lower. We can describe this by using the following formula
Thus , the integral for the work is:
hope this helps!!
That's true.
In fact, the resistance of a wire is given by:
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
We see that the resistance of the wire is inversely proportional to the cross-sectional area: A. Therefore, the narrower the wire, the smaller A, the larger the resistance. But higher resistance means that the current flowing through the wire is lower, therefore the flow of electrons in the circuit is slower, and the initial sentence is true.
In fact, the resistance of a wire is given by:
where
L is the length of the wire
A is the cross-sectional area of the wire
We see that the resistance of the wire is inversely proportional to the cross-sectional area: A. Therefore, the narrower the wire, the smaller A, the larger the resistance. But higher resistance means that the current flowing through the wire is lower, therefore the flow of electrons in the circuit is slower, and the initial sentence is true.