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2 years ago

15

What’s the ratio hcl:h2o

1 answer:

bixtya [17]2 years ago

6 0

Answer:

2:1

Explanation:

Write an equation for the reaction with hcl that gives h20 as one of the products

hcl +o2↔h20 +cl

then balance the equation

4hcl + o2↔2h20 +cl

4 : 2

simplify

2:1

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Why is Iron found as an Ore in the Earth

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$\huge \orange {\mathbb {Answer}}$

Ore is a deposit in Earth's crust of one or more valuable minerals. The most valuable ore deposits contain metals crucial to industry and trade, like copper, gold, and iron. Copper ore is mined for a variety of industrial uses. Copper, an excellent conductor of electricity, is used as electrical wire.

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3 years ago

Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc

marysya [2.9K]

Explanation:

1) $2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)$

$Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}$

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$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091$

2) $H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)$

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The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3$

3) $P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)$

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3 years ago

Why chemical industry important for the nation with its examples.

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2 years ago

Read 2 more answers

Write the chemical equation for the reaction of lithium hydroxide (LiOH) with an Arrhenius acid of your choosing. Name and write

Inessa05 [86]

<h3>Answer:</h3>

LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)

Salt formed is LiCl

<h3>Explanation:</h3>

Arrhenius acid refers to a substance that ionizes in water to generate protons or hydrogen ions.
Examples of Arrhenius acid include acids such as HCl, H₂SO₄ and HNO₃.
A reaction between Lithium hydroxide and an Arrhenius acid such as HCl will yield a salt and water.

That is;

LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)

The salt formed is LiCl
The reaction is an example of neutralization reaction.

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3 years ago

The rate constant for a certain reaction is measured at two different temperatures:

Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]$

$k_1$ = rate constant at temperature $T_1$ = $2.3\times 10^8$

$k_2$ = rate constant at temperature $T_2$ = $4.8\times 10^8$

$E_a$ = activation energy = ?

R= gas constant = 8.314 J/kmol

$T_1$ = temperature = $280.0^0C=(273+280)=553K$

$T_2$ = temperature = $376.0^0C=(273+376)=649K$

Putting in the values ::

$ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]$

$E_a=22689.8J/mol$

The activation energy Ea for this reaction is 22689.8 J/mol

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3 years ago