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Svetradugi [14.3K]
3 years ago
8

The net force on a car traveling at a constant speed in a straight line is zero. In which of these would the net force remain ze

ro?
A. The car speeds up to pass a big truck.

B. The car gets a flat tire and slows down.

C) In an instant the car comes to a complete stop.

D) The driver swerves around a piece of iron in the road.
Chemistry
1 answer:
dexar [7]3 years ago
5 0
I believe the answer is <span>In an instant the car comes to a complete stop. 

The net force is calculated through:
F = m x a
m = mass
a = Acceleration

When the car came into a complete stop, the acceleration become 0

Which means that


F = m x a

F = m x 0

F= 0 </span>
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Calculate the pressure exerted by an book of mass 20kg occupying an area of 2 m square.​
kotykmax [81]

The answer is 100 Pa.

The formula for calculating pressure is :

<u>Pressure = Force ÷ Area</u>

<u />

We are given that :

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  • area = 2 m²

We also know that :

<u>Force = mass ×g</u>

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So, force will be :

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How can you tell the number of covalent bonds an element can form?
Sergio039 [100]

The number of bonds for a neutral atom is equal to the number of electrons in the full valence shell (2 or 8 electrons) minus the number of valence electrons. This method works because each covalent bond that an atom forms adds another electron to an atoms valence shell without changing its charge.

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At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
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Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

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4 0
3 years ago
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zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

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Atomic mass of C = 12g

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