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harina [27]
3 years ago
10

State two differences between metals and non metals with respect to their

Chemistry
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

<u>Physical Properties</u>

1. Metals are shiny but most non - metals lack this property.

2. Metals are able to deform under compression (malleable) but most non - metals lack this property.

<u>Chemical Properties</u>

<u>1</u><u>.</u><u> </u><u>Metal</u><u>s</u><u> </u><u>are</u><u> </u><u>good</u><u> </u><u>conductors</u><u>of</u><u> </u><u>heat</u><u> </u><u>and</u><u> </u><u>electricity</u><u> </u><u>but</u><u> </u><u>most</u><u> </u><u>non</u><u> </u><u>-</u><u> </u><u>metals</u><u> </u><u>are</u><u> </u><u>insulators</u><u>.</u>

<u>2</u><u>.</u><u> </u><u>Metals</u><u>,</u><u> </u><u>when</u><u> </u><u>exposed</u><u> </u><u>to</u><u> </u><u>water</u><u> </u><u>atmospheric</u><u> </u><u>oxygen</u><u> </u><u>tend</u><u> </u><u>to</u><u> </u><u>rust</u><u> </u><u>but</u><u> </u><u>non</u><u> </u><u>-</u><u> </u><u>metals</u><u> </u><u>lack</u><u> </u><u>this</u><u> </u><u>chemical</u><u> </u><u>property</u>

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shutvik [7]

Answer:

1.9 × 10² g NaN₃

1.5 g/L

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles of N₂ formed

N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol

We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.

4.2 mol × 28.01 g/mol = 1.2 × 10² g

Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂

The mass ratio of NaN₃ to N₂ is 130.02:84.03.

1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃

Step 4: Calculate the density of N₂

We will use the following expression.

ρ = P × M / R × T

ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L

5 0
3 years ago
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victus00 [196]

Answer: Strictly a laboratory analysis and can only be done using the data obtained during analysis

Explanation:

To find a solution to this problem, you need to use the data collected during the lab work. A guide could be finding the possible forms of hydrated copper chlorides in reference books. Since it's also a lab work, you can definitely compare your data with lab mates.

The formula CuxCly.zH₂O and its name chloride hydrate already gives you an idea of the possibilities of the value of the integers, hence you can take a good guess for the identity of the unknown salt and calculate the theoretical formular weight for it. From the that you can proceed to also find the mass of water and copper from your lab analysis.  

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A mixture is when two or more <u>different</u> atoms/molecules are together, but not joined.

A substance is when the <u>same </u>atom/molecule is in a group together.

In this example, it is a substance because it is comprised of the same molecule not joined all together. If you wanted a mixture, other colored atoms/molecule (e.g. add green atoms) would change it to this property.

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