Answer:
A compact car, with mass 725 kg, ... at 115 km/h toward the east. ... b. A second car, with a mass of 2175 kg, has the same momentum. What is its ... Glisens : m = 2175 kg;. D 21,32 xrolka. anknown. r = ? 110.6 mis east
Explanation:
Answer:
Avoid downed power lines and stay away from buildings and bridges from which heavy objects might fall during an aftershock. Stay away until local officials tell you it is safe. A tsunami is a series of waves that may continue for hours. Do not assume that after one wave the danger is over.
Explanation:
answer is the 3rd law of motion
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Answer:
The value is the temperature of the air inside the tire
340.54 K
% of the original mass of air in the tire should be released 99.706 %
Explanation:
Initial gauge pressure = 2.7 atm
Absolute pressure at inlet
= 2.7 + 1 = 3.7 atm
Absolute pressure at outlet
= 3.2 + 1 = 4.2 atm
Temperature at inlet
= 300 K
(a) Volume of the system is constant so pressure is directly proportional to the temperature.
![\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%20%7D%7BT_%7B1%7D%20%7D%20%3D%20%5Cfrac%7BP_%7B2%7D%20%7D%7BP_%7B1%7D%20%7D)
![\frac{T_{2} }{300} = \frac{4.2}{3.7}](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%20%7D%7B300%7D%20%20%3D%20%5Cfrac%7B4.2%7D%7B3.7%7D)
340.54 K
This is the value is the temperature of the air inside the tire
(b). Since volume of the tyre is constant & pressure reaches the original value.
From ideal gas equation P V = m R T
Since P , V & R is constant. So
m T = constant
![m_{1} T_{1} = m_{2} T_{2}](https://tex.z-dn.net/?f=m_%7B1%7D%20%20T_%7B1%7D%20%3D%20%20m_%7B2%7D%20%20T_%7B2%7D)
![\frac{m_{2} }{m_{1} } = \frac{T_{1} }{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm_%7B2%7D%20%7D%7Bm_%7B1%7D%20%20%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20%7D%7BT_%7B2%7D%20%7D)
![\frac{m_{2} }{m_{1} } = \frac{300}{354.54}](https://tex.z-dn.net/?f=%5Cfrac%7Bm_%7B2%7D%20%7D%7Bm_%7B1%7D%20%20%7D%20%3D%20%5Cfrac%7B300%7D%7B354.54%7D)
![\frac{m_{2} }{m_{1} } =0.00294](https://tex.z-dn.net/?f=%5Cfrac%7Bm_%7B2%7D%20%7D%7Bm_%7B1%7D%20%20%7D%20%3D0.00294)
value of the original mass of air in the tire should be released is
![\frac{0.00294-1}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B0.00294-1%7D%7B1%7D)
⇒ -0.99706
% of the original mass of air in the tire should be released 99.706 %.