32? I could be wrong but I’m going with that answer choice
Answer:
An original funding source.
Explanation:
Non profit organization planned a marathon through which the money was raised for the vaccinations help, hence; here they are showing the original funding source, that is the number of runners and the amount raised by them.
The density of the nickel was greater than that of the quarter and penny, thus, the results supports the hypothesis.
<h3>What is density of substance?</h3>
The density of a substance is a measure of how tightly-packed the particles of the substance are.
Density is calculated as the ratio of the mass of the substance and the volume of the substance.
The hypothesis of the lab to compare the densities of a penny, a nickel, and a quarter is:
- If the nickel has a greater density than the quarter and penny, then it will have a greater mass to volume ratio. If the nickel has a lower density than the quarter and penny, then it will have a lower mass-to-volume ratio.
The average mass and the average volume of a penny, a nickel, and a quarter are then used to determine the density of each coin.
Based on obtained results, it would be found that the density of the nickel was greater than that of the quarter and penny. Therefore, the results supports the hypothesis.
In conclusion, the density of a substance depends on the mass and the volume.
Learn more about density at: brainly.com/question/1354972
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Answer:
v = 8.09 m/s
Explanation:
For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.
Let's calculate the energy
starting point. Higher
Em₀ = U = m gh
final point. To go down the slope
Em_f = K = ½ m v²
The work of the friction force is
W = fr L cos 180
to find the friction force let's use Newton's second law
Axis y
N - W_y = 0
N = W_y
X axis
Wₓ - fr = ma
let's use trigonometry
sin θ = y / L
sin θ = 11/110 = 0.1
θ = sin⁻¹ 0.1
θ = 5.74º
sin 5.74 = Wₓ / W
cos 5.74 = W_y / W
Wₓ = W sin 5.74
W_y = W cos 5.74
the formula for the friction force is
fr = μ N
fr = μ W cos θ
Work is friction force is
W_fr = - μ W L cos θ
Let's use the relationship of work with energy
W + ΔU = ΔK
-μ mg L cos 5.74 + (mgh - 0) = 0 - ½ m v²
v² = - 2 μ g L cos 5.74 +2 (gh)
v² = 2gh - 2 μ gL cos 5.74
let's calculate
v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74
v² = 215.6 -150.16
v = √65.44
v = 8.09 m/s
