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Scorpion4ik [409]
3 years ago
6

Which changes in an electric motor will make the motor stronger? Check all that apply. using a stronger permanent magnet using a

weaker permanent magnet increasing current in the electromagnet decreasing current in the electromagnet increasing the distance between the magnets decreasing the distance between the magnets
Physics
2 answers:
wariber [46]3 years ago
7 0
<h2>Answer:</h2>

The following changes will make the motor more stronger

  • <u>Using strong permanent magnets</u>
  • <u>Increasing the current</u>
  • <u>Decreasing the space between magnets</u>
<h2>Explanation:</h2>

Using string magnets will produce strong flux and the motor will become strong. The internal flux also deepness upon the strength of coil. Similarly by increasing current we can make the motor more powerful because according to power equation P=VI so increasing the current will increase the product of voltage and current resulting more power. In the same way by reducing the distance between magnets will make the motor stronger because the flux and torque will increase.

miv72 [106K]3 years ago
4 0
Use stronger magnets
increase current
push magnets closer to coil
adding more sets of coils
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If a 6V battery is connected to a light bulb whose resistance is 55,000Ω How much current will flow in the circuit?
notka56 [123]

Answer:

Current, I = 0.000109 Amps

Explanation:

Given the following data;

Voltage = 6V

Resistance = 55,000 Ohms

To find the current flowing through the circuit;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

V = IR

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Making current the subject of formula, we have;

I = \frac {V}{R}

Substituting into the formula, we have;

I = \frac {6}{55000}

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5 0
3 years ago
For a cylindrical capacitor, the capacitance does not depend on which of the following values?
IgorC [24]

Answer:

Capacitance of cylindrical capacitor does not depends on the amount of charge on the conductors

Explanation:

Consider a cylindrical capacitor of length L, inner radius R₁ and outer radius R₂, permitivity ε₀ constant then capacitance of cylindrical capacitor is given by:

C=\frac{2\pi \epsilon_{o}L}{ln\frac{R_{2} }{R_{1}} }

From this equation it is clear that capacitance of cylindrical capacitor is independent of the amount of charge on the conductors where as directly  proportional permitivity constant and length of cylinder where as inversely proportional to natural log of ratio of  R₂ and R₁

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Help, please!!!!!<br> I just need help putting the vocab word in the box where it belongs.
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8 0
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A 438kg car is accelerating east at 2.55m/s^2. What is the total force acting east on the car
lisabon 2012 [21]

Answer:

<h2>1116.9 N</h2>

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force = mass × acceleration

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force = 438 × 2.55

We have the final answer as

<h3>1116.9 N</h3>

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Nadusha1986 [10]

Force required to move a block is 1.615 N

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time = t = 8 sec

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