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3 years ago

The physical state in which a substance has a no definite volume is:

Chemistry

1 answer:

AlekseyPX3 years ago

7 0

The physical state in which a substance has no definite volume is gas.

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There are 24 hours in a day, 60 minutes in an hour, 7 days in a week, and 4 weeks in a month? using these conversions how many m

Serggg [28]

Explanation:

From your information above, assume 1 month is 28 days

1 days=24hours ; 28 days=672 hours (just multiply 1 days with 28)

1 hour=60minutes ; 672 hours=40,320 minutes

.. 1 month=40,320 minutes

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2 years ago

Compost from vegetable peelings can be used as plant fertilizer. * a. reduce b. resuse c. recycle d. recover

Arlecino [84]

Answer:

Is letter B

Explanation:

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2 years ago

formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?

kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally, the equation for the chemical equation is mathematically given as

HCOOH H^+ + HCOO

$\quad C-C \alpha \quad C \alpha$

$&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\$

$&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424$

Read more about chemical equation

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1 year ago

What does kinetic energy depends on

elena55 [62]

The kinetic energy of an object depends on two factors: mass(m) and velocity(v). The mass of an object can be measured in kilograms(kg) and velocity of the object in meters per second(m/s).

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3 years ago

g Tibet (altitude above sea level is 29,028 ft) has an atmospheric pressure of 240. mm Hg. Calculate the boiling point of water

Marina CMI [18]

<u>Answer:</u> The boiling point of water in Tibet is 69.9°C

<u>Explanation:</u>

To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg (Conversion factor: 1 atm = 760 mmHg)

$P_2$ = final pressure = 240. mmHg

$\Delta H_{vap}$ = Heat of vaporization = 40.7 kJ/mol = 40700 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature or normal boiling point of water = $100^oC=[100+273]K=373K$

$T_2$ = final temperature = ?

Putting values in above equation, we get:

$\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$342.9=T(^oC)+273\\T(^oC)=(342.9-273)=69.9^oC$

Hence, the boiling point of water in Tibet is 69.9°C

3 0

3 years ago