It is an employer's responsibility to provide training for special equipment. true false

Physics

1 answer:

Naddik [55]3 years ago

6 0

Answer:

True I hope you like it

Give me a brainliest answer

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As you run , your feet push on the ground with a force 500N . The ground pushes back on your feet with a force of 500N . (Please

Mademuasel [1]

Answer:

true

Explanation:

newtons third law says to every action there is always an equal and opposite reaction. so the answer is true

3 0

3 years ago

Read 2 more answers

Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va

julsineya [31]

Answer:

Acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

Explanation:

We have given electric field $E=5\times 10^6N/C$

Mass of proton is equal to $m=1.67\times 10^{-27}kg$

And charge on proton is equal to $e=1.6\times 10^{-19}C$

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to $F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N$

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So $1.67\times 10^{-27}\times a=8\times 10^{-13}$

$a=4.79\times 10^{14}m/sec^2$

So acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

5 0

3 years ago

Two objects, one having twice the mass of the other, are initially at rest. Two forces, one twice as big as the other, act on th

Elodia [21]

Note: There is no image to take as a reference, so I'm assuming F2 directed to the right and F1 to the left, and F2=2F1

Answer:

$\displaystyle a=\frac{F}{3M}$

to the right

Explanation:

Net Force

When several forces are applied to a particle or a system of particles, the net force is the sum of them all, considering each force as a vector. As for the second Newton's law, the total force equals the product of the mass by the acceleration of the system:

$\vec F_n=m\cdot \vec a$