Answer: 1.72cm
Explanation:
First let us calculate the mass of titanium that contain 2.86×10^23 atoms..
1mole of a substance contains 6.02x10^23 atoms as we have come to understand from Avogadro's hypothesis. Therefore, 1mole of titanium also contains 6.02x10^23 atoms.
1mole of titanium = 48g
1mole (i.e 48g) of titanium contains 6.02x10^23 atoms,
Therefore Xg of titanium will contain 2.86×10^23 atoms i.e
Xg of titanium = (48x2.86×10^23)/6.02x10^23 = 22.8g
Next, we must find the volume of titanium
Density of titanium = 4.5g/cm^3
Mass of titanium = 22.8g
Volume =?
Density = Mass /volume
Volume = Mass /Density
Volume = 22.8/4.5
Volume = 5.07cm^3
Now we can find the edge length:
Volume = 5.07cm^3
Length =?
V = L^3
L = cube root (V)
L = cube root (5.07)
L = 1.72cm
