<u>Given:</u>
Mass of ice = mass of water = 5.50 kg = 5500 g
Temperature of ice = -20 C
Temperature of water = 75 C
<u>To determine:</u>
Mass of propane required
<u>Explanation:</u>
Heat required to change from ice to water under the specified conditions is:-
q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)
= m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)
= 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ
The enthalpy change for the combustion of propane is -2220 kJ/mol
Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane
Molar mass of propane = 44 g/mol
Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g
Ans: 75.15 grams of propane must be combusted.
Answer:
When the following equation is balanced, what is the coefficient for HCl? Mg(s) + HCl(aq) -> MgCl2(aq) + H2(g) . 2. What are the coefficients that will balance the skeleton equation below? AlCl3 + NaOH -> Al(OH)3 + NaCl.
You will know;
1. know what products are
2. know how they work
Answer: 12L
Explanation:
To find the correct volume of the balloon, we can use the mathematical representation of Boyle’s law which states that a gas’s volume is inversely proportional to its pressure (as one increases the other decreases).
The equation for it is P1 * V1 = P2 * V2 where P1 and V1 represent the initial pressure and volume of the gas and P2 and V2 represent its changed temperature and volume.
In this case, the initial pressure of the gas inside the balloon is 3atm while its initial volume is 2.0L. Its pressure is then reduced to 0.5atm.
If we apply this information to the equation for Boyle’s law, we get
2L * 3atm = 0.5atm * V2.
Through arithmetic, we find that
6 = 0.5atm * V2
6/0.5atm = V2
12L = V2.
So, the volume of the balloon is 12L.
Hope this helps!
Answer:
Pb(NO₃)₂ ₍aq₎ + 2 KI ₍aq₎ ------------> PbI₂ ₍s₎ + 2 KNO₃ ₍aq₎
Explanation:
Chemical Equation:
lead(II) nitrate: Pb(NO₃)₂
potassium iodide: KI
lead(II) iodide: PbI₂
Potassium nitrate: KNO₃
Pb(NO₃)₂ ₍aq₎ + KI ₍aq₎ ------------> PbI₂ ₍s₎ + KNO₃ ₍aq₎
Balancing the equation:
For balancing the equation all atoms of the elements on both sides of equation i.e reactants and products are equal.
So balancing the above equation we get:
Pb(NO₃)₂ ₍aq₎ + 2 KI ₍aq₎ ------------> PbI₂ ₍s₎ + 2 KNO₃ ₍aq₎
