The question is incomplete, here is the complete question:
The solubility of substance X in water at a certain temperature is 35.7 g /100. g. Suppose that you have 330.0 g of substance X. What is the minimum volume of water you would need to dissolve it all? (Assume that the density of water is 1.00 g/mL.)
<u>Answer:</u> The minimum volume of water that would be needed is 940.17 mL
<u>Explanation:</u>
We are given:
Solubility of substance X in water = 35.1 g/100 g
This means that 35.1 grams of substance X is dissolved in 100 grams of water
Applying unitary method:
If 35.1 grams of substance X is dissolved in 100 grams of water
So, 330.0 grams of substance X will be dissolved in =
of water
To calculate the volume of water, we use the equation:

Density of water = 1 g/mL
Mass of water = 940.17 g
Putting values in above equation, we get:

Hence, the minimum volume of water that would be needed is 940.17 mL
False, because generally forensics collect the evidence to make sure the evidence doesn’t get damaged or tainted.... hope this helps
Answer:
is the equation of state of a hypothetical ideal gas
Explanation:
its formula is PV=nRT