Yes ... the law of reflection states that the angle of incidence is equal to the angle of reflection <em /><em>
it also states that the incident ray reflected ray and the normal at the point of incidence lie on the same plane....;
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Refer to the diagram shown below.
Let ω = the angular velocity (rad/s) of the wheel.
At the topmost point, the passenger, with mass m, will feel weightless if the passenger's weight matches the centripetal force.
The passenger's weight is mg.
The centripetal force is mω²r.
Therefore
mω²r = mg
ω = √(g/r)
Because g = 9.8 m/s² and r = 25/2 = 12.5 m, therefore
ω = √(9.8/12.5) = 0.8854 rad/s
Because 1 revolution per second is 2π rad/s, therefore

Answer: 8.455 rev/min
Answer: The taxi is moving with reference to A) Monument Circle. For each leg of the trip, the taxi's A) Average speed stays the same, but it's B) Average velocity changes.
Explanation: Brainliest Please!!!!
Answer:
the answer is number 2
Explanation:
because the weight of the scale is added
M₁V₁ = m₂V₂
<span>KE = ½mV² </span>
<span>½m₁V₁² = 2*½m₂V₂² </span>
<span>m₁V₁ = m₂V₂ </span>
<span>½m₁V₁² = m₂V₂² </span>
<span>m₁/m₂ = V₂/V₁ </span>
<span>m₁/m₂ = 2V₂²/V₁² </span>
<span>V₂/V₁ = √(½m₁/m₂) </span>
<span>m₁/m₂ = √(½m₁/m₂) </span>
<span>squaring</span>
<span>(m₁/m₂)² = ½m₁/m₂ </span>
<span>2m₂m₁² = m₁m₂² </span>
<span>divide by m₁m₂ </span>
<span>2m₁ = m₂ </span>
<span>m₂/m₁ = 2
hope this helps</span>