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1 year ago

What is so fragile that just saying its name breaks it?

Physics

1 answer:

sertanlavr [38]1 year ago

5 0

Answer: The Sound of Silence.

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A particle leaves the origin with a speed of 3.6 106 m/s at 34 degrees to the positive x axis. It moves in a uniform electric fi

Andrej [43]

Answer:

E = -4556.18 N/m

Explanation:

Given data

u = 3.6×10^6 m/sec

angle = 34°

distance x = 1.5 cm = 1.5×10^-2 m (This data has been assumed not given in

Question)

from the projectile motion the horizontal distance traveled by electron is

x = u×cosA×t

⇒t = x/(u×cos A)

We also know that force in an electric field is given as

F = qE

q= charge , E= strength of electric field

By newton 2nd law of motion

ma = qE

⇒a = qE/m

Also, y = u×sinA×t - 0.5×a×t^2

⇒y = u×sinA×t - 0.5×(qE/m)×t^2

if y = 0 then

⇒t = 2mu×sinA/(qE) = x/(u×cosA)

Also, E = 2mu^2×sinA×cosA/(x×q)

Now plugging the values we get

E = 2×9.1×10^{-31}×3.6^2×10^{12}×(sin34°)×(cos34°)/(1.5×10^{-2}×(-1.6)×10^{-19})

E = -4556.18 N/m

4 0

2 years ago

Redondear a dos decimales 12,4552

NikAS [45]

Answer:

12,46

Explanation:

esto se debe a que el número que está después del 5 en este caso 5 aumenta o eleva el valor aunque si es un número menor a 5 queda igua

4 0

3 years ago

Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .

Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

$t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h$

Next, you calculate the difference between both times t1 and t2:

$\Delta t=t_1-t_2=2.30h-1.875h=0.425h$

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

$0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s$

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0

2 years ago

In which situation is the object experiencing unbalanced forces

schepotkina [342]

Answer:

Explanation:

3 0

2 years ago

A rigid tank contains air at a pressure of 70 psia and a temperature of 55 ˚F. By how much will the pressure increase as the tem

Katyanochek1 [597]

Answer:

P_2 = 62.69 psi

Explanation:

given,

P₁ = 70 psia T₁ = 55° F = (55 + 459.67) R

P₂ = ? T₂ = 115° F = (115 + 459.67) R

we know,

p = ρ RT

ρ is the density which is constant

R is also constant

now,

$\dfrac{P_2}{P_1} =\dfrac{T_2}{T_1}$

$\dfrac{P_2}{70} =\dfrac{55+459.67}{115+459.67}$

P_2 = 62.69 psi

Hence, the increase in Pressure is equal to P_2 = 62.69 psi

7 0

2 years ago

What is so fragile that just saying its name breaks it?​

What is so fragile that just saying its name breaks it?