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goldfiish [28.3K]
3 years ago
5

If a temperature increase from 12.0 ∘C to 21.0 ∘C doubles the rate constant for a reaction, what is the value of the activation

barrier for the reaction
Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer:

53.7kJ/mol

Explanation:

Using Arrhenius equation

Given

T1 = 12°C = 273 + 12 = 285K

T2 = 21°C = 273 + 21 = 294K

k = A exp(-Ea/RT)

Where k = Rate constant

A = the pre-exponential factor

Ea = the activation energy

R = the Universal Gas Constant = 8.314J/kmol

T = the temperature

Taking logarithms of both sides of the Arrhenius Equation.

ln(k) = ln(A) - Ea/RT

If there are the rates at two different temperatures, we can derive the expression to be;

ln(k2/k1) = Ea/R(1/T1 - 1/T2)

The reaction doubles the rate constant

So, k2/k1 = 2 (Given)

Then we have

ln(2) = Ea/8.314(1/285 - 1/294)

ln(2) * 8.314 = Ea*(1/285 - 1/294)

6.9314E-1 * 8.314 = Ea*(1/285 - 1/294)

5.7628 = Ea*(1/285 - 1/294)

5.7628 = Ea*1.0741E-4

Ea = 5.7628 / 1.074E-4

Ea = 53657.35567970204J

Ea = 53.7kJ/mol

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Shtirlitz [24]

Answer:

The correct answer is c) 134L

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol.

1 atm x   V = 5, 98 mol x 0, 082 l atm / K mol x 273 K

V = 5, 98 mol x 0, 082 l atm / K mol x 273 K / 1 atm

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8 0
3 years ago
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
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Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

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Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

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MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

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6 0
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How many grams of fluorine are needed to generate 7.65 moles Carbon Tetrafluoride
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Answer:

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Explanation:

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2 years ago
Heat is transferred directly from a heat reservoir at 200 C to another heat reservoir at 5C. If the amount of heat transferred i
Daniel [21]

Answer:

ΔS=0.148  KJ/K

Explanation:

Given that

Q = 100 KJ

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T₂=5 + 273 = 278 K

Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.

So the total change in entropy given as

ΔS=  - Q/T₁ + Q/T₂

ΔS=  - 100/473 + 100/278  KJ/K

ΔS=0.148  KJ/K

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