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Juliette [100K]
3 years ago
15

What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

Chemistry
1 answer:
Darya [45]3 years ago
6 0

<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories

<u>Explanation:</u>

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

q=m\times L_{vap}

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

L_{vap} = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

q=10g\times 539Cal/g=5390Cal

Hence, the amount of energy absorbed by water is 5390 Calories

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