All categories

2 years ago

What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

1 answer:

Darya [45]2 years ago

6 0

Answer: The amount of energy absorbed by water is 5390 Calories

Explanation:

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

$q=m\times L_{vap}$

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

$L_{vap}$ = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

$q=10g\times 539Cal/g=5390Cal$

Hence, the amount of energy absorbed by water is 5390 Calories

You might be interested in

Basile [38]

The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6

6 0

3 years ago

sukhopar [10]

Isotopes are atoms of the same element that have different numbers of neutrons.

5 0

2 years ago

expeople1 [14]

"cg" is centigram, which is one-hundredth of a gram.

I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

$\frac{0.55g}{mL}*\frac{100cg}{1g}*\frac{1000mL}{1L}=55,000\frac{cg}{L} \ or \ 5.5e4\frac{cg}{L}$

3 0

3 years ago

kakasveta [241]

The answer that i got was three
i redid it and got some answer like 4.62 x1014 Hz

3 0

2 years ago

Marysya12 [62]

4 moles of water are produced

Explanation:

4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as $5H_{2} +2O_{2} --> 4H_{2} O + H_{2}$
This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.

4 0

3 years ago