Answer:
The weakest oxidizing agent is Zn^2+(aq)
The strongest reducing agent is Zn(s)
The strongest oxidizing agent is I2(s)
The weakest reducing agent is I^-(aq)
I^- cannot reduce Zn^2+ to Zn(s)
I2(s) can be reduced by hydrogen gas
Explanation:
In looking at oxidizing and reducing agents, our primary guide is the reduction potentials of each specie. The more negative the reduction potential of a specie, the better its function as a reducing agent. Zn has a very negative reduction potential hence it a very good reducing agent. Similarly, iodine has a very positive reduction potential hence it is a good oxidizing agent.
Only a specie having a more negative reduction potential than zinc can reduce it in aqueous solution. Similarly, the reaction potential of hydrogen is less than that of iodine hence hydrogen gas can reduce iodine.
Answer:
b
Explanation:
beacuse when u reduce the concentration
Charles law states that volume of gas is directly proportional to volume of gas at constant pressure
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
where
V - volume
T - temperature in kelvin
T1 - 123 °C + 273 = 396 K
T2 - 468 °C + 273 = 741 K
substituting the values
V = 38.29 L
new volume is 38.29 L
Answer:
Explanation:1. A 2.650-g sample of a gas occupies a volume of 428 mL at 0.9767 atm and 297.3 K. What is its molar mass?
2.
a. A sample of nitrogen gas has a volume of 10.0 L at 2.50atm and 50.0℃. If the pressure is increased to 5.00 atm and the temperature decreases to 25.0℃, what volume does the gas occupy?
(a). 5.00L, (b).4.61L, (c).2.50L, (d).5.42L
b. Using the average bond energy, calculate the enthalpy of the above reaction. draw Lewis structures of the reactants and products first to determine the exact bond order. N2(g)+3H2(g)→2NH3(g)
Please, you have to apply the formula below:<span>Q=c∗m∗Δt</span>where Q is the energy lost, c is the specific heat of water, m is the mass of water involved, so m=3.75 *10^-1 Kg c=4,184 J/(Kg*°C) delta t=37.5 °C
Taking density of water as 1000kg/m3. Mass of water would be 0.375kg. So, heat lost would be<span>H=mCDeltaT</span>H=0.375*4184*37.5 = 58837.5J