Answer:
0.012 N
Explanation:
The formula to apply is that adopted from the Ampere law which is;
F= μ* I₁*I₂*l /2πd where
F is force that one conductor exerts on the other.
μ = magnetic permeability of free space = 4π×10⁻⁷ T. m/A
I₁ = current in conductor one=10 A
I₂ = current in conductor two= 10 A
l= length of conductor= 3 m
d= distance between the conductors = 5 mm = 0.005 m
Applying the values in the equation
F= 4π×10⁻⁷ *10*10*3 / 2π*0.005
F= 6 * 10⁻⁵ / 0.005
F=0.012 N
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Answer:
(a) The work done is 0.05 J
(b) The force will stretch the spring by 3.8 cm
Explanation:
Given;
work done in stretching the spring from 30 cm to 45 cm, W = 3 J
extension of the spring, x = 45 cm - 30 cm = 15 cm = 0.15 m
The work done is given by;
W = ¹/₂kx²
where;
k is the force constant of the spring
k = 2W / x²
k = (2 x 3) / (0.15)²
k = 266.67 N/m
(a) the extension of the spring, x = 37 cm - 35 cm = 2 cm = 0.02 m
work done is given by;
W = ¹/₂kx²
W = ¹/₂ (266.67)(0.02)²
W = 0.05 J
(b) force = 10 N
natural length L = 30 cm
F = kx
x = F / k
x = 10 / 266.67
x = 0.0375 m
x = 3.75 cm = 3.8 cm
Thus a force of 10 N will stretch the spring by 3.8 cm
