Answer:
31.6 m/s
Explanation:
Mass is conserved, so the mass flow at the outlet of the pump equals the mass flow at the nozzle.
m₁ = m₂
ρQ₁ = ρQ₂
Q₁ = Q₂
v₁A₁ = v₂A₂
v₁ πd₁²/4 = v₂ πd₂²/4
v₁ d₁² = v₂ d₂²
Now use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Since h₁ = 0 and P₂ = 0:
P₁ + ½ ρ v₁² = ½ ρ v₂² + ρgh₂
Writing v₁ in terms of v₂:
P₁ + ½ ρ (v₂ d₂²/d₁²)² = ½ ρ v₂² + ρgh₂
P₁ + ½ ρ (d₂/d₁)⁴ v₂² = ½ ρ v₂² + ρgh₂
P₁ − ρgh₂ = ½ ρ (1 − (d₂/d₁)⁴) v₂²
Plugging in values:
579,160 Pa − (1000 kg/m³)(9.8 m/s²)(15 m) = ½ (1000 kg/m³) (1 − (1.99 in / 3.28 in)⁴) v₂²
v₂ = 31.6 m/s
Answer:
E = 0.437 N/C
Explanation:
Given that,
Charge, 
Electric force, 
Let the strength of the electric field is E. We know that, the electric force is given by :
F = qE
Where
E is the electric field strength
So, the strength of the electric field is equal to 0.437 N/C.
Answer:
V = 4.48m/s a = 1.57m/s²
Explanation:
ω₀ = 16rad/s
α₀ = 5.6rad/s²
r = 280mm = 0.28m
a = ?
v = ?
Angular velocity (ω₀) = velocity of acceleration / length of path
ω₀ = v / r
V = ω₀ * r
V = 16 * 0.28
V = 4.48m/s
Acceleration = ?
Angular acceleration α₀ = angular velocity (ω) / time take (t)
α₀ = ω / t .... equation i
But acceleration (a) = velocity (v) / time (t)
a = v / t
t = v / a
Put t = v / a into equation i
α₀ = ω / (v / a)
α₀ = ω * a / v
α * v = ω * a
a = (α * v) / ω
a = (5.6 * 4.48) / 16
a = 1.568m/s²
a = 1.57m/s²
The answer is B.It decreases the change of the momentum of the person
a.) Relative velocity = velocity of car B - velocity of car A
= 19 - 14
= 5 m/s
Hope this cleared your doubt, feel free to ask any question regarding this and have a nice day ahead! :)
