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Mama L [17]
3 years ago
14

Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,

Hf = –241.82 kJ/mol) according to the equation below. What is the enthalpy of combustion (per mole) of C4H10 (g)? Use .
Chemistry
1 answer:
WITCHER [35]3 years ago
6 0

Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

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Can one atom in this type of reaction win the "tug of war"? What might happen if it did?
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Which answer below correctly identifies the type of change and the explanation for the boiling of water?
Lynna [10]

physical change because even though gas formation was observed, the water was undergoing a  state change, which means that its original properties  are preserved

Explanation:

The boiling of water is a physical change because the original properties of the water is preserved.

  • A physical change is the one that alters the physical properties of matter.
  • This kind of change is easily reversible as the water can be cooled back.
  • No new kinds of matter is produced in this kind of change .
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During the boiling of water, intermolecular bonds called hydrogen bonds between the water molecules are broken. This makes the individual molecules free.

Learn more:

Hydrogen bonds brainly.com/question/10602513

#learnwithBrainly

7 0
3 years ago
What is the name of this hydrocarbon? 2-butane 2-butene 2-butyne 4-butyne 4-propyne
monitta
2-butane is the correct answer
5 0
3 years ago
Read 2 more answers
Express the ratio 1:<br><img src="https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%20%7D%7B8%7D%20" id="TexFormula1" title="1 \frac{1 }{8
tester [92]

Explanation:

To out this fraction in its simplest form, you need to multiply the 8 by the 1 and then add the 1 in the numerator.

You end up getting

\frac{9}{8}

Answer:

\frac{9}{8}

3 0
3 years ago
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