earth exerts a downward gravitational force of 8.9 n on a cake that is resting on a plate. the plate exerts a force of 11.0 n up
ward on the cake, and a knife exerts a downward force of 2.1 n on the cale.
1 answer:
See the free-body diagram in attachment. (please rotate it such that N points upward)
Explanation:
The free body diagram (FBD) of an object is a diagram representing all the forces acting on a body. Each force is represented using an arrow, where:
- The length of the arrow is proportional to the magnitude of the force
- The direction of the arrow shows the direction of the force
In this problem, we have 3 forces acting on the cake:
- The force of gravity, downward, of magnitude (mg) (where m is the mass of the cake and g is the acceleration of gravity), equal to 8.9 N
- The force exerted by the knife on the cake, F = 2.1 N, acting downward
- The normal reaction exerted by the plate on the cake, N = 11.0 N, acting upward
The 3 forces are shown in the diagram attached. We also notice that the vector sum of all the forces is zero, in fact:
This means that the acceleration of the cake is zero, so the cake is in equilibrium.
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Explanation:
The given data is as follows.
Angular velocity () = 2.23 rps
Distance from the center (R) = 0.379 m
First, we will convert revolutions per second into radian per second as follows.
= 2.23 revolutions per second
=
= 14.01 rad/s
Now, tangential speed will be calculated as follows.
Tangential speed, v =
= 0.379 x 14.01
= 5.31 m/s
Thus, we can conclude that the tack's tangential speed is 5.31 m/s.