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jasenka [17]
3 years ago
13

The literature value for the density of aluminum is 5.6 g/mL. If an experimenter calculates a value of 5.2g/mL, what is their pe

rcent error?
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

We have the final answer as

<h2>7.14 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 5.6 g/mL

error = 5.6 - 5.2 = 0.4

The percentage error is

P(\%) =  \frac{0.4}{5.6}  \times 100 \\  = 7.142857...

We have the final answer as

<h3>7.14 %</h3>

Hope this helps you

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rjkz [21]

Answer:

                       1.66 × 10⁻¹⁸  Moles

Explanation:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

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Neptunium-237 was the first isotope of a transuranium element to be discovered. the decay constant is /s. what is the half-life
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brainly.com/question/1491386

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