Question

The literature value for the density of aluminum is 5.6 g/mL. If an experimenter calculates a value of 5.2g/mL, what is their percent error?

Answer 1

Answer:

We have the final answer as

7.14 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual density = 5.6 g/mL

error = 5.6 - 5.2 = 0.4

The percentage error is

$P(\%) = \frac{0.4}{5.6} \times 100 \\ = 7.142857...$

We have the final answer as

7.14 %

Hope this helps you