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lyudmila [28]
3 years ago
9

Objects 1 and 2 collide and stick together. Which best describes the momentum of the resulting single object? It is less than th

e momentum of object 1 but greater than the momentum of object 2. It is greater than the momentum of object 1 but less than the momentum of object 2. It is equal to the momentum of object 1 minus the momentum of object 2. It is equal to the momentum of object 1 plus the momentum of object 2.
Chemistry
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

The answer would be D

Explanation:

Hope I helped <3

Vinil7 [7]3 years ago
4 0

Answer:

the anser D

Explanation:

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2. When two forces act on an object in opposite directions, you calculate the net
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When two forces act on an object in opposite directions, the net  force can be calculated by subtracting the two forces.

<u>Explanation:</u>

  • The net/final force by subtracting the two given opposite forces as asked in the above question.

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The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

Best regards.

8 0
3 years ago
Read 2 more answers
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