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lyudmila [28]
3 years ago
9

Objects 1 and 2 collide and stick together. Which best describes the momentum of the resulting single object? It is less than th

e momentum of object 1 but greater than the momentum of object 2. It is greater than the momentum of object 1 but less than the momentum of object 2. It is equal to the momentum of object 1 minus the momentum of object 2. It is equal to the momentum of object 1 plus the momentum of object 2.
Chemistry
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

The answer would be D

Explanation:

Hope I helped <3

Vinil7 [7]3 years ago
4 0

Answer:

the anser D

Explanation:

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What was the action between the 2 atoms in an ionically bonded compound that caused that ionic bond to form in the first place?
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Ionic bonds form between two elements that have a very large difference in electronegativity ie. a metal and a non-metal. The electronegative element will want an electron to make it stable whilst the less electronegative element wants to donate an electron to make it stable. Therefore the metallic element donates a electron to the non-metal and both become ions, which attract each other. Eg. Na becomes Na+ and Cl becomes Cl-, the opposite charges attract, forming the bond.
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3 years ago
Explain it to you or more sentences using your own words what you learned about biomes organisms and populations
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5 0
3 years ago
Liquidification of gases​
larisa86 [58]

Answer:

the process by which substances in their gaseous state are converted to the liquid state.

Explanation:

When pressure on a gas is increased, its molecules closer together, and its temperature is reduced, which removes enough energy to make it change from the gaseous to the liquid state.

6 0
3 years ago
Br2(l) + 2Nal(aq) — 12(s) + 2NaBr(aq)
Ganezh [65]

Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.

To determine which elements are oxidized and reduced,

First, we will define the terms Oxidation and Reduction

<em>Oxidation </em>is simply defined as the loss of electrons. It can also be defined as increase in oxidation number.

<em>Reduction </em>is defined as the gain of electrons. It can also be defined as decrease in oxidation number.

The given chemical equation is

Br₂(l) + 2NaI(aq) → I₂(s) + 2NaBr(aq)

Oxidation number of Bromine decreased from 0 to -1.

Therefore, Bromine is reduced.

Oxidation number of Iodine increased from -1 to 0.

Therefore, Iodine is oxidized.

Oxidation number of sodium did not change.

Therefore, Sodium is neither oxidized nor reduced.

Hence, Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.

Learn more here: brainly.com/question/12913997

3 0
2 years ago
How many moles of calcium chloride are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4
Georgia [21]

Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.

Explanation : Given,

Moles of HCl = 2.6 moles

Moles of Ca(OH)_2 = 1.4 moles

Now we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is:

2HCl+Ca(OH)_2\rightarrow 2H_2O+CaCl_2

From the balanced reaction we conclude that

As, 2 mole of HCl react with 1 mole of Ca(OH)_2

So, 2.6 moles of HCl react with \frac{2.6}{2}=1.3 moles of Ca(OH)_2

From this we conclude that, Ca(OH)_2 is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CaCl_2

From the reaction, we conclude that

As, 2 mole of HCl react to give 1 mole of CaCl_2

So, 2.6 moles of HCl react to give \frac{2.6}{2}=1.3moles of CaCl_2

Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.

7 0
4 years ago
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