Question

two kilogram of nasialo4 zeolites are used in a water filter to remove calcium. after complete ion exchange the zeolite is removed from the filter and weighed. what is the new weigh of the zeolite [answer in kilogram]

Answer 1

After ion exchange with zeolite in water filter to remove calcium by substitute natrium ion with calcium ion, the weight of zeolite become 1.9578 kg.

ion exchange calculation can be done by using basic stoichiometry if we know how the reaction of the ion exchange. In this case where zeolite with natrium ion will be exchanged with calcium. The reaction of exchange will be like this:

$2NaSiAlO_{4} + Ca^{2+}$ ⇒ $Ca(SiAlO_{4}) _{2} + 2Na^{+}$

Calculate the molecule weight of both zeolite
Atomic weight data:
Na = 23 gram/mole

Si = 28 gram/mole

Al = 27 gram/mole

O = 16 gram/mole

Ca = 40 gram/mole

Molecule weight

$NaSiAlO_{4}$ = 142 gram/mole

$Ca(SiAlO_{4}) _{2}$ = 278 gram/mole

Calculate mole from 2kg of zeolite with natrium :

2000 gram/ 142 = 14.0845 mole

Based on the stoichiometry, we got the mole of zeolite with calcium:

14.0845 mole x 1/2 = 7.0423 mole

Weight of zeolite after the ion exchanged with calcium:

7.0423 mole x 278 = 1957.8 gram = 1.9578 kg

Learn more about ion exchange here: brainly.com/question/28203551

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