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4 years ago

What is the main function of the excretory system?

Physics

2 answers:

tiny-mole [99]4 years ago

6 0

Answer: To collect and remove wastes from the body.

Explanation:

The excretory system helps to collect and remove wastes from the body in the form of urine.

lilavasa [31]4 years ago

3 0

Answer:

Explanation:

because the rest arent it

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Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will

denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

$W_{net} = \Delta K$

Also, $\Delta K = K_{initial} - K_{final}$

= $(0 - 4.0 \times 10^{-17})$ J

= $-4.0 \times 10^{-17}$ J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

w = -Fd

$-4.0 \times 10^{-17} J = -F \times 0.3 m$

F = $1.33 \times 10^{-16}$

Therefore, relation between electric field and force is as follows.

E = $\frac{F}{q}$

= $\frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}$

= $0.831 \times 10^{3}$ C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is $0.831 \times 10^{3}$ C.

3 0

4 years ago

A car with two people traveling down the road has a mass of 100 kg and a velocity of 5 m/s. The car pulls over and picks up two

Oliga [24]

Answer:

750 kg.m/s

Explanation:

Momentum is the product of mass and velocity in kg.m/s.

In this case, initial momentum⇒p=m × v where m is mass and v is velocity

initial mass of car m₁=100 kg

Initial velocity of car v₁=5 m/s

Initial momentum= 100×5= 500 kg.m/s

New mass after picking two extra people m₂= 150 kg

Velocity stays the same v₂=v₁= 5 m/s

New momentum= m₂× v₂

p=150×5=750 kg.m/s

4 0

3 years ago

Read 2 more answers

A wheel is rotating about an axis that is in the z direction The angular velocity ωz is 6.00 rad s at t 0 increases linearly wit

Amanda [17]

A) $+1.67 rad/s^2$

The angular acceleration of the wheel is given by

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

where

$\omega_i = -6.00 rad/s$ is the initial angular velocity of the wheel (initially clockwise, so with a negative sign)

$\omega_f = 4.00 rad/s$ is the final angular velocity (anticlockwise, so with a positive sign)

$\Delta t= 6.00 s - 0=6.00 s$ is the time interval

Substituting into the equation, we find the angular acceleration:

$\alpha = \frac{4.00 rad/s - (-6.00 rad/s)}{6.00 s}=+1.67 rad/s^2$

And the acceleration is positive since the angular velocity increases steadily from a negative value to a positive value.

B) 3.6 s

The time interval during which the angular velocity is increasing is the time interval between the instant $t_1$ where the angular velocity becomes positive (so, $\omega_i=0$ ) and the time corresponding to the final instant $t_2 = 6.0 s$ , where $\omega_f = +6.00 rad/s$ . We can find this time interval by using

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

And solving for $\Delta t$ we find

$\Delta t = \frac{\omega_f - \omega_i}{\alpha}=\frac{+6.00 rad/s-0}{+1.67 rad/s^2}=3.6 s$

C) 2.4 s

The time interval during which the angular velocity is idecreasing is the time interval between the initial instant $t_1=0$ when $\omega_i=-4.00 rad/s$ ) and the time corresponding to the instant in which the velovity becomes positive $t_2$ , when $\omega_f = 0 rad/s$ . We can find this time interval by using

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

And solving for $\Delta t$ we find

$\Delta t = \frac{\omega_f - \omega_i}{\alpha}=\frac{0-(-4.00 rad/s)}{+1.67 rad/s^2}=2.4 s$

D) 5.6 rad

The angular displacement of the wheel is given by the equation

$\omega_f^2 - \omega_i^2 = 2 \alpha \theta$

where we have

$\omega_i = -6.00 rad/s$ is the initial angular velocity of the wheel

$\omega_f = 4.00 rad/s$ is the final angular velocity

$\alpha=+1.67 rad/s^2$ is the angular acceleration

Solving for $\theta$ ,

$\theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}=\frac{((+6.00 rad/s)^2-(-4.00 rad/s)^2}{2(+1.67 rad/s^2)}=5.6 rad$

3 0

3 years ago

PLZ HELP

marissa [1.9K]

We just keep meeting huh? I believe the wave to be longitudinal, because the energy is going left to right.

7 0

4 years ago

What is air pressure?

dolphi86 [110]

Answer:

A. Earth's gravity pulling down on air molecules

Explanation:

Air pressure refers to the weight of the air per unit surface area. It is the amount of gravitational force which is pulling down the molecules of air.

The common unit of air pressure is: Pascal, atm

1 atm = 101325 Pa

As the column of the air above increases, the air pressure increase. This is because with the increase in amount of air, the weight increase of the air increases. This is the reason a diver feels immense pressure in the sea and cooking takes a lot of time on hilly areas because of low air pressure.

5 0

3 years ago